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Mathematics 19 Online
OpenStudy (eskelle):

What is an equation in standard form of an ellipse centered at the origin with vertex (-6,0) and co-vertex (0,4)?

OpenStudy (eskelle):

i can show the answers if needed but i want to know how to do it

OpenStudy (plainntall):

What is the standard form of an ellipse centered on the origin?

OpenStudy (eskelle):

i dont know

OpenStudy (plainntall):

Isn't it something like \[\frac{ x^2 }{ a^2 }+\frac{ y^2 }{ b^2 }=1\]

OpenStudy (eskelle):

idk tbh ive been slacking off all year

OpenStudy (plainntall):

It is. I am just trying to get you to think about it. You should probably review the topic and then approach the problem again.

OpenStudy (eskelle):

i dont have time to review the topic, the semester ends tonight

OpenStudy (eskelle):

what do you do to the equation?

OpenStudy (plainntall):

Let's draw a picture. |dw:1465511047621:dw|

OpenStudy (eskelle):

okay so how do you write an equation based on the vertexes?

OpenStudy (plainntall):

The major axis is the a value in the equation and that is equal to 6 since the vertex is 6 units from the origin. The y value is 4 which is the b value in the equation and it is the minor axis. So now you have enough information to complete the equation.

OpenStudy (eskelle):

i dont know what major and minor axis means?

OpenStudy (plainntall):

|dw:1465511327859:dw|

OpenStudy (eskelle):

so they just mean x and y axis

OpenStudy (eskelle):

when putting them into equation are they x and y?

OpenStudy (plainntall):

Yes so a=6 b=4 \[\frac{ ^{x^2} }{ a^2 }+\frac{ y^2 }{ b^2 }=1\]

OpenStudy (eskelle):

so x^2/6^2+y^2/4^2=1? is that it or do you have to do more or simplify the denominator

OpenStudy (plainntall):

I would simply, but you got it right \[\frac{ x^2 }{ 36 } + \frac{ y^2 }{ 16 }=1\]

OpenStudy (eskelle):

oh ok thank you. thank you for your patience as well

OpenStudy (plainntall):

You are welcome :)

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