Question

What values for theta(0 9 years ago

Answer 1

this is the rest of the problem, just too much to type out

Answer 2

what values for theta(0 less than or equal to theta less than or equal to 2 pi) satisfy the equation? 3sin theta = sin theta -1
3sinx=sinx-1

3sinx-sinx=-1
2sinx=-1
sinx=-1/2
x=7π/6,11π/6 (in quadrants III and IV where sin<0)

Answer 3

2sinθcosθ + √2cosθ = 0 , 0 ≤ θ ≤ 2π

cosθ(2sinθ + √2) = 0

So, cosθ = 0 or sinθ = -√2/2

If cosθ = 0, then θ = π/2, 3π/2

If sinθ = -√2/2, then θ = 5π/4, 7π/4

Answer 4

Let x = theta

2sin(x)cos(x) + cos(x)√2 = 0


Factor out cos(x).

cos(x)(2sin(x) + √2) = 0


Set cos(x) equal to zero.

cos(x) = 0

x = π/2
x = 3π/2

The solutions are

x = π/2 and x = 3π/2

Answer 5

hope that helps

Answer 6

those arent options

Answer 7

@hannahaz has solved the first half

you also need to solve \(\Large \sin(\theta) + \sqrt{2} = 0\) to get the other two solutions

Answer 8

what is theta equal to again

Answer 9

oh nvm, @hannahaz wrote this out `If sinθ = -√2/2, then θ = 5π/4, 7π/4`

Answer 10

but i dont see that as an option? unless i am just blind what letter is it

Answer 11

all the options have 4

Answer 12

well you combine the 2 sets of values to get these four values total

π/2, 3π/2, 5π/4, 7π/4

Answer 13

each factor will have 2 solutions
there are 2 factors so 2*2 = 4 solutions total

Answer 14

ok so thats the final answer?

Answer 15

yes

Answer 16

thank you

Answer 17

np