Question

(4/√2) + (2/√3) = ?
a) (4√3 + 2√2) / (√5)
b) (4√3 + 2√2) / (√6)
c) (6) / (√2 + √3)
d) (6) / (√5)
e) (8) / (√6)

Answer 1

i chose d. but i think its wrong

Answer 2

\[\frac{ 4 }{ \sqrt{2} }+\frac{ 2 }{ \sqrt{3} }\]

Answer 3

i added them straight across... not sure if the same denominator still works if they are roots

Answer 4

Get a common denominator
\[\frac{ 4\sqrt{3} }{ \sqrt{2}\sqrt{3}}+\frac{ 2\sqrt{2} }{ \sqrt{2}\sqrt{3}}\]

Answer 5

the LCD of sqrt3 and sqrt 2 is sqrt 6
to get the denominator multiply each term by sqrt 6

Answer 6

Can you see where this is going yet?

Answer 7

well the denominators equal √5 and √5... i dont think you add them. Yea! no adding!
the numerators dont change. sooo B.

Answer 8

\[\frac{ 4\sqrt{3}+2\sqrt{2} }{ \sqrt{6} }\]
based on
\[\sqrt{a}\sqrt{b}=\sqrt{ab}\]
I don't think they want you to crunch numbers. I think they want you to use your understanding of how products of square roots relate.

Answer 9

ohhhh times not add.

Answer 10

thanks you guys!

Answer 11

:)