Question

What is the solution of the system? Use substitution.

3x + 2y = 7

y = –3x + 11

A.
(6, –3)

B.
(6, –7)

C.


D.
(5, –4)

Answer 1

Do you know how to start this

Answer 2

We know that y equals \(\large{-3x+11}\) for the second equation...since we know of y we can substitute this equation where y is in the first equation soo...

\(\Huge{3x+2(-3x+11)=7}\)

In which you would simplify to find x...

Answer 3

@Er.Mohd.AMIR the "asker" is offline. Do you have a question about this?

Answer 4

what?

Answer 5

i know how to solve it i have no q about this one

Answer 6

ok bye

Answer 7

3x + 2y = 7(eqn1)

y = –3x + 11(eqn2)

3x + 2(-3x + 11) = 7
3x -6x + 22 = 7
-3x +22 = 7
-3x = 7-22
-3x = -15
3x = 15
x = 15/3
x = 5

Now ,we either place x = 5 in eqn1 or eqn2

I'll put in eqn1
3x + 2y = 7
3(5) + 2y = 7
15 + 2y = 7
2y = 7-15
2y = -8
y =-8/2
y = -4

Therefore the solution is (5,-4)