State
@jim_thompson5910
So we're dealing with this? \[\Large f(x) = \frac{x+9}{x^2+2x+3}\]
did this help at all? http://2.bp.blogspot.com/-9uxn3U5jEz8/VC-TK4qZudI/AAAAAAAAAGc/zt-dgnMHBfw/s1600/Screen%2BShot%2B2014-10-03%2Bat%2B11.26.10%2BPM.png
sort of, what i got from the diagram is that my problem IS a horizontal asymptote, is that right?
which case will apply here? 1? 2? 3?
and that I'm not sure of..
is n < m true? is n = m true? is n > m true?
its either x, 0, or 9
m>n
think of \(\Large x+9\) as \(\Large x^1+9\)
yes or n < m
yes
since n < m, this means that the x axis is the horizontal asymptote that's another way of saying "the equation y = 0 is the horizontal asymptote"
oh, so thats it y=0 is the horizontal asymptote? That makes a lot of sense!
y = 0 lies perfectly on top of the x axis
so its right? and can i have help with one more??
sure
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