Tia is investing $ 2500 that she would like to grow to $ 6000 in 10 years, at what annual interest rate compounded quarterly must Tia invest her money? I know that PV = 6000 A= 2500 i = ? n = 40 My teacher gave us the formula PV = A (1+i) -n I am having troubles isolating i, I am not sure how to get to the right answer
use the compound interest formula A = P(a + r/t) ^ nt where P is the starting amount , r = annual rate in decimal form, t = number of times interest is pais in a year and n = number of years
So how would I get rid of thee exponent? square root?
plug in the given values first 6000 = 2500( 1 + r/4)^40
Im confused as to why it is r/4
is it because i = r/N
because the interest is paid 4 times a year r = annual rate
That is what they ask for - annual rate.
alright that makes sense
so if we divide both sides by 2500 to isolate the exponent part we get (1 + r/4)^40 = 2.4 now take logs of both sides
why do we log?
Sorry I just want to make sure I understand this well so I can do it again later
- that gets rid of the exponenents
alright so I log the other side
the side witht he 2.4
is this inverse log or just log?
what? I somehow lost my post!!???
take logs - u can use natural logs:- ln (1 + r/4)^40 = ln 2.4 by law of logs 40 ln (1 + r/4) = ln2.4 ln ( 1 + r/4) = ln2.4 / 40 ok so far?
I think so, so by doing log I will be getting rid of the 40 exponent?
yea
Alright that makes sense
so I have 0.380211242 = 1+ r/4
now work out right side ln (1 + r/4) = 0.0218867
Wait how is it 0.021, Im not sure why Im getting a diffrerent number
0.021 = ln (1 + r/4) now you can use inverse logs
you should use 0.0218867 to get accurate result
use the e^x key on ur calculator - remember we are using natural logs
Alright I think I understand now
( 1 + r/4) = e^0.021887
good you should get a result which is between 8 and 9%
Aim to isolate the expression you want to evaluate and then takes logs note we use the log law log a^n = n log a
It's nice to deal with someone who wants the learn rather than just get an answer.
Alright I think that should be alright then, thank you very very much!!
yw
Join our real-time social learning platform and learn together with your friends!