Question

Beyond Euclidean Geometry help!
http://prntscr.com/bfayy9
http://prntscr.com/bfayzu

Answer 1

*barfs* I rather kms than to go through this again

Answer 2

Have you done this before?

Answer 3

yeah but I never paid attention because it suck.s

Answer 4

@jim_thompson5910

Answer 5

I'm not sure if he knows that subject. Last semester, I asked him about real analysis and he was nooooooooooooooooooo

Answer 6

If you have done this before, then you must know how to do it. Also, he helped me with Hamiltonian graphs before :)

Answer 7

but I slept in class every lecture and I had a chilled out professor who curved like crazy and didn't have mandatory homework so :P

Answer 8

What have you tried so far on problem 1 ?

Answer 9

I formed my answer. Do you mind checking it? @jtvatsim

Answer 10

Sure I can take a look :)

Answer 11

Okay.
This is Part A:
http://prntscr.com/bfbf84

Answer 12

This is Part B:
http://prntscr.com/bfbfo4

Answer 13

I agree with part A :)

Answer 14

Question Part C: http://prntscr.com/bfbgh9

Answer Part C: http://prntscr.com/bfbg8w

Answer 15

I think you have the idea for part B. Basically, to start and end at the same point is an Euler Circuit. However, an Euler Circuit must have only even vertices. But obviously we have two odd vertices, so not all the vertices are even. Thus, it is mathematically impossible.

Answer 16

Okay thanks so much. Can you check Part C for me? :)

Answer 17

And... part C looks good. You are right to say that this is a Hamiltonian circuit. :) Good work!

Answer 18

Thank you so much!! I was having a really difficult time with this question, so I'm glad I got them right and I appreciate you taking the time to check them.

Answer 19

No worries! Looks like you used the properties correctly and turned potentially hard problems into fairly easy ones. :)