Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (legomyego180):

Ten minutes until assignment is due...can anyone help me with this question?

OpenStudy (legomyego180):

zepdrix (zepdrix):

Ok using our basic techniques, do you understand how to find f'(x)?

OpenStudy (legomyego180):

It is given isnt it?

zepdrix (zepdrix):

\(\large\rm f(x)=-3g(x)+5x+5\) \(\large\rm f'(x)=?\)

OpenStudy (legomyego180):

-3g(x)+5

zepdrix (zepdrix):

Hmm you didn't differentiate your g(x)? :O

OpenStudy (usukidoll):

that is some weird formatting :/ find the derivative of f where is the g(x) anyway?

zepdrix (zepdrix):

Why did g(x) stay the same when you took derivative of f(x)?

OpenStudy (usukidoll):

:P nevermind. through the weird formatting, I found it

OpenStudy (legomyego180):

according to the info g'(x) @ 5 is 2x-2

OpenStudy (usukidoll):

whoa whoa whoa y = g(x) y = 2x-2 so 2x-2=g(x)?

OpenStudy (usukidoll):

zepdrix is right, you need the derivative of g(x) as well because there's product rule going on for f(x) = -3g(x) term

zepdrix (zepdrix):

No product rule. You just simply didn't take a derivative of the entire first term.

OpenStudy (usukidoll):

-3g(x) leave -3 alone deal with g(x) which is g'(x) + leave g(x) deal with -3 which is 0 due to -3 being a constant. unless you're treating g(x) as a constant too.

OpenStudy (legomyego180):

Im a little lost

zepdrix (zepdrix):

Where you at banana man? You simply forgot to take the derivative of the first term. \(\large\rm f(x)=-3g(x)+5x+5\) \(\large\rm f'(x)=-3g'(x)+5\) understand?

OpenStudy (legomyego180):

yea definitely. back on track.

zepdrix (zepdrix):

So now we evaluate this derivative at x=-5, \(\large\rm f'(-5)=-3g'(-5)+5\)

OpenStudy (usukidoll):

you need g(x) to grab the derivative of g(x) because finding f'(-5) ahahahhahah ... stuckage

zepdrix (zepdrix):

If y=2x-2 is the equation of the line tangent to g(x) at x=-5, then g'(-5) gives us THE SLOPE of that equation, ya?

OpenStudy (legomyego180):

Yup

OpenStudy (legomyego180):

-12

zepdrix (zepdrix):

So which value is the slope in the equation? y=2x-2 m=2, yes? Therefore g'(-5)=2.

zepdrix (zepdrix):

-12?? Hmm...

OpenStudy (usukidoll):

y=g(x) y=2x-2 g(x) = 2x-2 g'(x) = 2

OpenStudy (legomyego180):

I put 41 but got it wrong

OpenStudy (usukidoll):

g'(-5) = 2 so now f'(-5) = -3g'(-5)+5 we know that g'(-5) = 2 so plug that in f(-5) = -3(2)+5 now solve that

OpenStudy (usukidoll):

shoots forgot the ' for f'(-5)

OpenStudy (usukidoll):

f'(-5) = -3g'(-5)+5 we know that g'(-5) = 2 so plug that into the equation f'(-5) = -3(2)+5 now solve

OpenStudy (legomyego180):

got it, thanks

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!