Question

Solve the differential equation.

Answer 1

\[xy^2y' = x + 4\]

Answer 2

\[y^2y' = \frac{ x+4 }{ x }=>\int\limits_{}^{}y^2dy = \int\limits_{ }^{}(1+\frac{ 4 }{ x })dx\]\[\frac{ 1 }{ 3 }y^3=x+4lnx+C\]\[y^3=3x+12lnx+C\]\[y = (3x+12\ln \left| x \right|)^{1/3}\]

Answer 3

I am getting the answer wrong. What do?

Answer 4

Have you tried leaving your C inside the cube root?
\[y = (3x + 12\ln|x| + C)^{1/3}\]

Answer 5

Tried that. The question doesn't state to put a constant.

Answer 6

and there aren't any initial conditions given like y(0) = 1 or anything? I can't see any mistakes in your work, it looks correct.

Answer 7

I wonder if its being stupid and wants "3C" ...

Answer 8

Tried 3C

Answer 9

lol, what the heck?

Answer 10

Okay, I found it. Turns out, it wanted " y = . . . " /derp

Answer 11

wow