Solve the following equation: x^2-2x+1=0 Please help!
how do I do this problem?
x=1
thx
@hedgepig do you know how to find it? there are two methods you could use
well we just started this unit... i have no idea what im doing :(
alright so quadratic equations are in the form \[ax^{2}+bx+c \]
see the 2 there? in the exponent that's the highest degree of our polynomial
the -2?
so the way i see this is that because the highest power is we should expect 2 solutios \[x^{2} ~~~~2~solutions \]
\[ax^{2}+bx+c ~~~ x^{2}-2x+1\] @hedgehog can you identify the a b and c terms by just comparing the two?
hmmm ok 0, -2, and 1?
no wait 0, -2. and 0
so the a term is in-front of the x^2 , b term is the number in front of x
so theres nothing in front of the x^2 term? doesnt that mean its 0??
no it means that there is a 1
\[x^{2} --> 1(x^{2})\] but no one really writes it like that
ohhh ok so 1,-2,0?
first two are right . see that 1 there that's your c value
but it doesnt have an x? doesnt that mean its 0?
no c is a constant because there isn't an x there
say if I gave you this \[3x^{2}+2x+1\] what would your a b and c terms be? this will make sense in a bit.
2 and 0?
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