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Solve the differential equation, small question on concept.
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\[sinx \frac{ dy }{ dx }+(cosx)y = 9\sin(x^2)\]
The 2nd step becomes \[sinx \frac{ dy }{ dx }+y*\frac{ d(sinx) }{ dx }= 9 \sin(x^2)\] then 3rd step \[\frac{ d(y*sinx )}{ dx }=9\sin(x^2)\] Why does cosx change into \[\frac{ d(sinx) }{ dx }\]?
The derivative of sin x is cos x
Are you sure its\[\sin(x^2)\]
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