Look at the figure below: Triangle EFD has the measure of angle EFD equal to 60 degrees. G is a point on side DF. Points E and G are joined by a straight line. Angle DEG measures 60 degrees. Make a two-column proof showing statements and reasons to prove that triangle DEF is similar to triangle DGE.
One second, I'll get a better picture.
Also, if anyone would like to give a detailed explanation of why their answer is true, it would be appreciated.
So let's think. How do we prove similarity?
Through things like AAA, meaning all angles are the same, or SSS, as in all sides are the same.
is it AAA or AA?
AA, typo.
Okay. So let's look at the picture. are we given similar sides or are we given congruent angles?
Congruent angles
I got that far before I got stuck on where to go next.
I was thinking of whether side EG was an altitude, but that wasn't stated.
Ok
So with setting angle D as x
Made a mistake; let me look at this problem. One moment.
Ah, ok.
Proceed with setting that angle as x. I read the problem wrong; tried to prove two of the wrong triangles are similar. Oops.
Ok
So with because angle D = D by the reflexive property
And angle DEG = DFE by the definition of congruent angles
Yes.
That means triangle DEF should be similar to triangle DFE by AA-similarity
Yup.
Wait, said the wrong triangle
meant triangle DEG ~ DFE
Apologies, I'm not checking the specifics here... good catch
Thanks
Looks like you more or less got this one on your own, but feel free to continue post more questions if you find difficulties.
Ok, thanks!
One last question: What is the principle that states triangle DFE would be similar to triangle DEF?
You already stated it. AA-similarity
:P Oh yea
I kept on thinking there was some special principle for it, thanks
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