Given: AB and CD If the coordinates of point A are (8, 0) and the coordinates of point B are (3, 7), the y-intercept of AB is ________. If the coordinates of point D are (5, 5), the equation of line CD is y = _____ x + _____.
@AdoNine @Michele_Laino
here we have to write the equation of the line which passes at points A and B, first
Okay
the slope \(m\) of such line, is given by the subsequent computation: \[m = \frac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}} = \frac{{7 - 0}}{{3 - 8}} = ...?\]
please complete
7/5?
hint: \(3-8=-5\)
7/-5?
correct!
so thats the first part?
the requested equation, is: \[\begin{gathered} y - {y_2} = m\left( {x - {x_2}} \right) \hfill \\ \hfill \\ y - 0 = \frac{{ - 7}}{5}\left( {x - 8} \right) \hfill \\ \end{gathered} \] please simplify
y=-7/5x+56/5 is correct ?
correct! Next the requested \(y-\)intercept, is the value of \(y\), when \(x=0\), so we have: \[y = \frac{{ - 7}}{5} \cdot 0 + \frac{{56}}{5} = ...?\]
y=56/5 ?
correct!
for second part, I think that coordinates of point C are missing
So for the last question I would put y=56/5x+...?
we need to know the coordinates of point C
Or what would you put after x+ ?
On the question it does not have any coordinates for c.
how point C is defined?
line CD is parallel to line AB, namely, the symbol: \[AB \parallel CD\] means line AB is parallel with respect to line CD
now, parallel lines have the same slope, so the slope of line CD is \(m=-7/5\)
the requested equation, is therefore: \[y - 5 = \frac{{ - 7}}{5}\left( {x - 5} \right)\] please simplify
hint: if we apply the distributive property, we get: \[y - 5 = \frac{{ - 7x}}{5} + 7\]
And when I simp. that what I plug into the last part?
y=-7/5x+12?
yes! Please we have this step: I add \(5\) to both sides, so I get: \[y - 5 + 5 = \frac{{ - 7x}}{5} + 7 + 5\] please simplify
correct!
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