AB and BC form a right angle at point B. If A = (-3, -1) and B = (4, 4), what is the equation of BC?
x + 3y = 16
2x + y = 12
-7x − 5y = -48
7x − 5y = 48
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OpenStudy (austinlr12):
@Michele_Laino
OpenStudy (austinlr12):
@AdoNine
OpenStudy (michele_laino):
here, we have to write the equation of line AB first
OpenStudy (adonine):
yes
OpenStudy (michele_laino):
the slope \(m\) of such line is:
\[m = \frac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}} = \frac{{ - 1 - 4}}{{ - 3 - 4}} = ...?\]
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OpenStudy (austinlr12):
5/7?
OpenStudy (austinlr12):
Would the answer be 7x − 5y = 48 ?
OpenStudy (michele_laino):
correct!
I think it is suffice so
since line BC is perpendicular to line AB, then its slope \(m'\) has to check this identity:
\(m \cdot m'=-1\)
namely:
\[m' = \frac{{ - 1}}{m} = \frac{{ - 1}}{{5/7}} = ...?\]
OpenStudy (adonine):
@austinlr12 you are correct
OpenStudy (austinlr12):
Thxs
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OpenStudy (michele_laino):
Please wait, I'm checking...
and the requested equation, is therefore:
\[y - 5 = \frac{{ - 7}}{5}\left( {x - 5} \right)\]
OpenStudy (michele_laino):
oops.. I have made a typo:
\[y - 4 = \frac{{ - 7}}{5}\left( {x - 4} \right)\]