AB and BC form a right angle at point B. If A = (-3, -1) and B = (4, 4), what is the equation of BC? x + 3y = 16 2x + y = 12 -7x − 5y = -48 7x − 5y = 48
@Michele_Laino
@AdoNine
here, we have to write the equation of line AB first
yes
the slope \(m\) of such line is: \[m = \frac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}} = \frac{{ - 1 - 4}}{{ - 3 - 4}} = ...?\]
5/7?
Would the answer be 7x − 5y = 48 ?
correct! I think it is suffice so since line BC is perpendicular to line AB, then its slope \(m'\) has to check this identity: \(m \cdot m'=-1\) namely: \[m' = \frac{{ - 1}}{m} = \frac{{ - 1}}{{5/7}} = ...?\]
@austinlr12 you are correct
Thxs
Please wait, I'm checking... and the requested equation, is therefore: \[y - 5 = \frac{{ - 7}}{5}\left( {x - 5} \right)\]
oops.. I have made a typo: \[y - 4 = \frac{{ - 7}}{5}\left( {x - 4} \right)\]
I got this equation: \[7x + 5y = 48\]
I already submit the answer...
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