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Mathematics 21 Online
OpenStudy (mathmusician):

Calculus optimization problem help please fan and medal!!

OpenStudy (mathmusician):

I need help with #4 please

OpenStudy (mathmusician):

Here are some screenshots because some people don't like opening pdf files

OpenStudy (mathmusician):

@agent0smith

OpenStudy (agent0smith):

The initial investment will be given by the V(t) formula. \[\Large I_0 = C e^{k \sqrt t}\]since that is the value of the card when he sells it and thus invests the money. Then just plug that into the formula for the given investment formula.

OpenStudy (mathmusician):

so i subsitute t for 65 years?

OpenStudy (agent0smith):

No. You don't know when he sells the card, just that it's t years after t=0. t is how long he held onto the card. Which means the time in the investment formula A(t) has to be 40-t... since, for example, if he keeps the card for 10 years then sells it, then he'd have invested the money in his account for the other 30 years (till he's 65) \[\Large A(t) = I_0 e^{r(40-t)}\]then just plug in the Io expression from above.

OpenStudy (mathmusician):

so it would be \[A(t)=(Ce ^{k \sqrt{t}})e ^{r(40-t)}\]

OpenStudy (agent0smith):

Right. The most confusing part was figuring out the time in the equations, with the way the question is worded. But since the t for holding/selling the card is anywhere from 0 to 40, the time for investing must be 40-t.

OpenStudy (mathmusician):

Okay that makes sense thanks mate!!

OpenStudy (agent0smith):

Welcome.

rebeccaxhawaii (rebeccaxhawaii):

Wow, brain goals. Good job, danno!

OpenStudy (mathmusician):

haha good job indeed

OpenStudy (mathmusician):

This is what the graph would look like for c = 2500, k=0.5, and r=0.06?

OpenStudy (agent0smith):

Keep in mind 0<t<40...he's not gonna live 200 years.

OpenStudy (mathmusician):

so the graph only counts after y = 2500?

OpenStudy (agent0smith):

Well probably, but i'm saying restrict the domain. You can and maybe should also simplify using exponent rules, adding the e exponents: \[\Large A(t)=(Ce ^{k \sqrt{t}})e ^{r(40-t)} = C e^{k \sqrt t+ r(40-t)}\]

OpenStudy (mathmusician):

Okay i will try to graph that one then

OpenStudy (agent0smith):

\[\Large A(t)= 2500 e^{0.5 \sqrt t+ 0.06(40-t)}\] but make sure to restrict the domain.

OpenStudy (mathmusician):

okay

OpenStudy (mathmusician):

i would restrict it to 65 because it is 65 years?

OpenStudy (mathmusician):

or what do i restrict it to

OpenStudy (agent0smith):

The question literally tells you the t domain. And i gave the same thing a few posts back.

OpenStudy (mathmusician):

Yeha my bad i saw that after i posted the question

OpenStudy (mathmusician):

i feel stupid now

OpenStudy (mathmusician):

thanks mate!!

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