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Mathematics
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OpenStudy (errinss):
how do i finish this, i need it to be y=mx+b
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OpenStudy (errinss):
\[y=\frac{ 21+6x }{ 7 }\]
OpenStudy (errinss):
do i just take 7 from 21 or do i take 7 from both?
OpenStudy (nincompoop):
you can reduce the constant, k, value by dividing 21 by 7
OpenStudy (agent0smith):
You can split up the fractions, like this example: \[\large \frac{ 10+7a }{b } = \frac{ 10 }{ b }+\frac{ 7a }{ b }\]
OpenStudy (errinss):
would 6x still be 6x alone or will it be a fraction through out the problem?
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OpenStudy (nincompoop):
it won't be alone because you can't reduce or simply it.
OpenStudy (errinss):
thought so THX!! XP
OpenStudy (agent0smith):
Using the example i gave above as a guide, split this up \[\large \frac{ 21+6x }{ 7 } = ?\]
OpenStudy (nincompoop):
no worries, good luck with your studies
OpenStudy (errinss):
\[Y=\frac{ 21 }{ 7 }+\frac{ 6x }{ 7 }\]
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OpenStudy (nincompoop):
ya simplify the constant 21/7 since it is reducible
OpenStudy (errinss):
3 then 6x/7 stays the same
OpenStudy (nincompoop):
yes you don't say then
just use the addition operation
OpenStudy (nincompoop):
\(y = \dfrac{6x}{7}+3 \)
OpenStudy (errinss):
okay lol thx
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