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Mathematics 15 Online
OpenStudy (errinss):

how do i finish this, i need it to be y=mx+b

OpenStudy (errinss):

\[y=\frac{ 21+6x }{ 7 }\]

OpenStudy (errinss):

do i just take 7 from 21 or do i take 7 from both?

OpenStudy (nincompoop):

you can reduce the constant, k, value by dividing 21 by 7

OpenStudy (agent0smith):

You can split up the fractions, like this example: \[\large \frac{ 10+7a }{b } = \frac{ 10 }{ b }+\frac{ 7a }{ b }\]

OpenStudy (errinss):

would 6x still be 6x alone or will it be a fraction through out the problem?

OpenStudy (nincompoop):

it won't be alone because you can't reduce or simply it.

OpenStudy (errinss):

thought so THX!! XP

OpenStudy (agent0smith):

Using the example i gave above as a guide, split this up \[\large \frac{ 21+6x }{ 7 } = ?\]

OpenStudy (nincompoop):

no worries, good luck with your studies

OpenStudy (errinss):

\[Y=\frac{ 21 }{ 7 }+\frac{ 6x }{ 7 }\]

OpenStudy (nincompoop):

ya simplify the constant 21/7 since it is reducible

OpenStudy (errinss):

3 then 6x/7 stays the same

OpenStudy (nincompoop):

yes you don't say then just use the addition operation

OpenStudy (nincompoop):

\(y = \dfrac{6x}{7}+3 \)

OpenStudy (errinss):

okay lol thx

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