Can someone help me find the seventh roots of j
is that the complete question?
Yes Find the seventh roots of j (Remember j is equivalent to 0+1j) that is all it says
perhaps it is what we usually call \(i\) aka \(\sqrt{-1}\) is that possible?
Yeah 'j' in electrical engineering is same as 'i' in math
yes instead of "i" we use "j"
oooh well this will be no joy, but totally doable' do you know how to write \(j\) in trig form or exponential form?
yes im familiar but i am mostly using polar form, exponential form and rectangular form
then write it in polar form, divide the angle by 7
then add \(2\pi\) to the angle, divide by 7 again do this seven times
but you cant divide by 0, in order to find the angle you have to do inverse tangent right?
\[j = 1\angle 90 = x^7\] Your goal here is to find all x that satisfy above equation
oh no no no you do not use inverse tangent (although you can) just look at a picture
|dw:1465873100424:dw|
Remember this rule ? \[(r\angle \theta )^n = r^n \angle n\theta\]
no what does it mean/
It is same as demoivre thm in polar form
oh
oh ok
and do i fill in "K" using the number 1-6
no idea what K is but the first root would be \[\cos(\frac{\pi}{14})+j\sin(\frac{\pi}{14})\]
Can you find one root by staring at \[x^7 = 1\angle 90\] ?
since the picture makes it pretty clear that \(\theta=\frac{\pi}{2}\) and when you divide by 7 you get \(\frac{\pi}{14}\)
\[1e ^{j1.57}\]
How ?
changed it to radian
you writing in exponential from it is the same just \[\huge e^{\frac{\pi}{14}i}\]
Could you keep it in fraction form please as I'm on mobile and can't know whatvyiuve done to get 1.57 ?
to get 1.57 i multiplied 90 by pi then divided by 180
shouldn't i find the seventh root of 1
forget fractions, the answers are irrational
you mean the real seventh root of 1???? yes you need it , but it is 1 for sure
You could leave the angle as pi/2 instead of writing in decimal form 1.57
yeah ok i think i got it
is dividing 360 by 7 required
Have you found one root by staring at the previous equation ?
0+1j ?
\[x^7=1\angle 90\] Let the required root x in polar form be \(r\angle \theta\) \[(r\angle \theta)^7=1\angle 90\] Using demoivres thm this becomes \[r^7\angle 7\theta=1\angle 90\]
Comparing the magnitude and angle both sides \[r^7=1\] \[7\theta = 90\]
Oh sorry bout that it was required to be written in rectangular form
You can convert it back to rectangular form in the end. Multiplication and exponenets are easier to work in polar form
i get you now all thats left is for me to find the other 5, thanks alots
Okay good. So what is one root from above eqns ?
180
No
Its easy if you understand what exactly I'm asking
arnt they suppose to have the same size angles between each others
\[r^7 = 1\] \[7\theta = 90\]
oh the same size between 7 angles
Can you simply solve \(r\) and \(\theta\) from above two equations ?
r=1 \[\theta \approx12.86\]
Yes, but it looks nice if you leave it as a fraction 90/7
ok and i am adding this number
Maybe first convince yourself that \(1\angle 90/7\) is indeed a 7th root of j
it is similar to another equation i did finding the third roots
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