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Algebra 7 Online
OpenStudy (akimi):

Can someone help me find the seventh roots of j

OpenStudy (triciaal):

is that the complete question?

OpenStudy (akimi):

Yes Find the seventh roots of j (Remember j is equivalent to 0+1j) that is all it says

satellite73 (satellite73):

perhaps it is what we usually call \(i\) aka \(\sqrt{-1}\) is that possible?

ganeshie8 (ganeshie8):

Yeah 'j' in electrical engineering is same as 'i' in math

OpenStudy (akimi):

yes instead of "i" we use "j"

satellite73 (satellite73):

oooh well this will be no joy, but totally doable' do you know how to write \(j\) in trig form or exponential form?

OpenStudy (akimi):

yes im familiar but i am mostly using polar form, exponential form and rectangular form

satellite73 (satellite73):

then write it in polar form, divide the angle by 7

satellite73 (satellite73):

then add \(2\pi\) to the angle, divide by 7 again do this seven times

OpenStudy (akimi):

but you cant divide by 0, in order to find the angle you have to do inverse tangent right?

ganeshie8 (ganeshie8):

\[j = 1\angle 90 = x^7\] Your goal here is to find all x that satisfy above equation

satellite73 (satellite73):

oh no no no you do not use inverse tangent (although you can) just look at a picture

satellite73 (satellite73):

|dw:1465873100424:dw|

ganeshie8 (ganeshie8):

Remember this rule ? \[(r\angle \theta )^n = r^n \angle n\theta\]

satellite73 (satellite73):

no what does it mean/

ganeshie8 (ganeshie8):

It is same as demoivre thm in polar form

satellite73 (satellite73):

oh

OpenStudy (akimi):

oh ok

OpenStudy (akimi):

and do i fill in "K" using the number 1-6

satellite73 (satellite73):

no idea what K is but the first root would be \[\cos(\frac{\pi}{14})+j\sin(\frac{\pi}{14})\]

ganeshie8 (ganeshie8):

Can you find one root by staring at \[x^7 = 1\angle 90\] ?

satellite73 (satellite73):

since the picture makes it pretty clear that \(\theta=\frac{\pi}{2}\) and when you divide by 7 you get \(\frac{\pi}{14}\)

OpenStudy (akimi):

\[1e ^{j1.57}\]

ganeshie8 (ganeshie8):

How ?

OpenStudy (akimi):

changed it to radian

satellite73 (satellite73):

you writing in exponential from it is the same just \[\huge e^{\frac{\pi}{14}i}\]

ganeshie8 (ganeshie8):

Could you keep it in fraction form please as I'm on mobile and can't know whatvyiuve done to get 1.57 ?

OpenStudy (akimi):

to get 1.57 i multiplied 90 by pi then divided by 180

OpenStudy (akimi):

shouldn't i find the seventh root of 1

satellite73 (satellite73):

forget fractions, the answers are irrational

satellite73 (satellite73):

you mean the real seventh root of 1???? yes you need it , but it is 1 for sure

ganeshie8 (ganeshie8):

You could leave the angle as pi/2 instead of writing in decimal form 1.57

OpenStudy (akimi):

yeah ok i think i got it

OpenStudy (akimi):

is dividing 360 by 7 required

ganeshie8 (ganeshie8):

Have you found one root by staring at the previous equation ?

OpenStudy (akimi):

0+1j ?

ganeshie8 (ganeshie8):

\[x^7=1\angle 90\] Let the required root x in polar form be \(r\angle \theta\) \[(r\angle \theta)^7=1\angle 90\] Using demoivres thm this becomes \[r^7\angle 7\theta=1\angle 90\]

ganeshie8 (ganeshie8):

Comparing the magnitude and angle both sides \[r^7=1\] \[7\theta = 90\]

OpenStudy (akimi):

Oh sorry bout that it was required to be written in rectangular form

ganeshie8 (ganeshie8):

You can convert it back to rectangular form in the end. Multiplication and exponenets are easier to work in polar form

OpenStudy (akimi):

i get you now all thats left is for me to find the other 5, thanks alots

ganeshie8 (ganeshie8):

Okay good. So what is one root from above eqns ?

OpenStudy (akimi):

180

ganeshie8 (ganeshie8):

No

ganeshie8 (ganeshie8):

Its easy if you understand what exactly I'm asking

OpenStudy (akimi):

arnt they suppose to have the same size angles between each others

ganeshie8 (ganeshie8):

\[r^7 = 1\] \[7\theta = 90\]

OpenStudy (akimi):

oh the same size between 7 angles

ganeshie8 (ganeshie8):

Can you simply solve \(r\) and \(\theta\) from above two equations ?

OpenStudy (akimi):

r=1 \[\theta \approx12.86\]

ganeshie8 (ganeshie8):

Yes, but it looks nice if you leave it as a fraction 90/7

OpenStudy (akimi):

ok and i am adding this number

ganeshie8 (ganeshie8):

Maybe first convince yourself that \(1\angle 90/7\) is indeed a 7th root of j

OpenStudy (akimi):

it is similar to another equation i did finding the third roots

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