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Chemistry 7 Online
OpenStudy (melzie):

I AM SO LOST! please help me... PICTURE OF THE QUESTION IN COMMENTS...

OpenStudy (melzie):

OpenStudy (melzie):

@mathmate

OpenStudy (mathmate):

This is a question of weighted averages. Question gives: w1=98.90% of C-12 and w2=1.100% C13. The average atomic mass would be given by w1*AMU(C-12)+w2*(AMU(C-13) Do not forget to change w1 and w2 into decimals before multiplying, i.e. w1=0.9890, w2=0.01100 The number of significant figures equals that least number of significant figures of the data, namely that of w1.

OpenStudy (melzie):

so it would look like:\[(12.000000)(0.9890)+(13.003354(0.01100)\]

OpenStudy (amtran_bus):

Exactly

OpenStudy (mathmate):

@melzie Exactly! You need a rather accurate calculator/software to do the calculations, and you have to decide on the number of significant figures for your result. A step which is very important in chemistry and physics.

OpenStudy (melzie):

Thank you so much! I think i understand it now :)

OpenStudy (mathmate):

You're welcome! Thank you for the testimonial. At first sight I thought it was a sarcasm, but then I realized that you meant to thank me for not having given a direct answer! Whew! Have a great day! :)

OpenStudy (melzie):

oh sorry i didnt mean it sarcastically lol

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