∆ABC is reflected across the x-axis and translated 2 units up to give the image ∆A'B'C' with coordinates A'(1, 1), B'(2, -1), C'(2, 1). What are the coordinates of the preimage ∆ABC?

A. A(-1, 1), B(-2, 3), C(-2, 1)
B. A(1, 1), B(2, 3), C(2, 1)
C. A(1, -3), B(2, -1), C(2, -3)
D. A(1, -3), B(2, -5), C(2, -3)

Question

∆ABC is reflected across the x-axis and translated 2 units up to give the image ∆A'B'C' with coordinates A'(1, 1), B'(2, -1), C'(2, 1). What are the coordinates of the preimage ∆ABC?

A. A(-1, 1), B(-2, 3), C(-2, 1)
B. A(1, 1), B(2, 3), C(2, 1)
C. A(1, -3), B(2, -1), C(2, -3)
D. A(1, -3), B(2, -5), C(2, -3)

fruitcakeninja · Answer

No image?

_malice_ · Answer

Nope
Doesn't give me one

fruitcakeninja · Answer

Then im stumped

_malice_ · Answer

Same ;-;

fruitcakeninja · Answer

GTG

_malice_ · Answer

Same

_malice_ · Answer

I have like 8 minutes before I need to go, so thanks for the help and gudbai ;)

mehek14 · Answer

Reflected across the x axis:

(x, y) -> (x, -y)

mehek14 · Answer

Translated up 2 units:

(x, y) - > (x, y + 2)

mehek14 · Answer

They gave u the new image coordinates so we have to do the reverse

mehek14 · Answer

Start with A'(1, 1)

First we have to bring it down 2 units

(1, 1-2) -> ?

_malice_ · Answer

Whup, I have to leave now :) I will come back to this however, thank you so much and sorry I don't have more time.

mehek14 · Answer

You're welcome and it's alright :)

_malice_ · Answer

I habe returned