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Mathematics 13 Online
OpenStudy (kimberly_pr):

Can someone help me use the combination formula?

OpenStudy (kimberly_pr):

There are 40 volunteers for the research study on the Power Pill. Each subgroup of the study will contain 10 participants. Determine how many ways these participants can be selected and explain your method.

OpenStudy (kimberly_pr):

And I know the answer is 847,660,528

OpenStudy (bigbosssaint21):

https://prezi.com/gf0b680vvkuv/algebra-2-honors-project/

OpenStudy (agent0smith):

Delete all the tags and unnecessary crap so people see the question. "40 volunteers for the research study on the Power Pill. Each subgroup of the study will contain 10 participants." So from 40 people, choose 10. 40 choose 10. 40C10

OpenStudy (kimberly_pr):

The combination formula is:

OpenStudy (calculusxy):

Since we know that we need to work with \(40C10\), we can work with the formula. Basically, 40 is \(n\) and 10 is \(r\) since \(nCr\). Substitute those points back into the formula: \[\large \frac{40!}{10! (40-10)!} = \frac{40!}{10! 30!}\]

OpenStudy (kimberly_pr):

Ohh, ok, makes sense. And then the exclamation mark means everything below that number, right? So like 40! = 40, 39, 38, 37...

OpenStudy (agent0smith):

Yep You can either simplify, or plug into a calc

OpenStudy (kimberly_pr):

Ok, that's what I thought. Thanks so much, both of you!

OpenStudy (kimberly_pr):

Now that you guys helped with part 1, can you help with part 2? It uses a permutation instead of a combination. @agent0smith @calculusxy

OpenStudy (kimberly_pr):

There are 15 research doctors participating in the study and the research board needs to be established with the offices of director, assistant director, quality control analyst, and correspondent. (Doctors can only hold one office on the research board.) Determine how many ways this research board can be chosen and explain your process

OpenStudy (kimberly_pr):

And the answer for this one is 32,760

OpenStudy (agent0smith):

Since the positions are different, use permutations. From 15 you're putting 4 into an order (4 positions), so 15P4

OpenStudy (kimberly_pr):

Ok, and the formula for permutations is:

OpenStudy (kimberly_pr):

So the 15 is n, and the 4 is r right? Because "15P4" like you said @agent0smith

OpenStudy (agent0smith):

Yes, sorry got busy

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