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Mathematics 10 Online
OpenStudy (19mkolli):

A test diagnoses a disease correctly 92% of the time when a person has the disease and 80% of the time when a person doesn't have the disease. Approximately 4% of the people in the United States have the disease. Find the probability that a randomly selected is correctly diagnosed by the test.

OpenStudy (agent0smith):

So 4% of the pop. has the disease, they will be tested correctly 92% of the time (so multiply) 96% of the pop. doesn't have it, and will be tested correctly 80% of the time Add those two products.

OpenStudy (19mkolli):

so it would be the sum of (0.04*0.92) and (0.96*0.8)?

OpenStudy (19mkolli):

which would equal 80.48%

OpenStudy (agent0smith):

Looks reasonable, since it should be close to 80% anyway, since most people don't have the disease, and it's 80% correct for people who don't

OpenStudy (19mkolli):

so it would be correct?

OpenStudy (19mkolli):

Ok so the last 3 questions are as follows

OpenStudy (19mkolli):

There are 562 students in the sophomore class, of them 185 play chess, and 50 play a sport, and 210 are in a club. If 12 students do all three, and 27 are in a club and play a sport, 81 are only in a club, and 47 play chess and a sport.

OpenStudy (19mkolli):

Using the above information, create a Venn Diagram

OpenStudy (agent0smith):

Make a new question, it's a three way venn diagram.

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