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Mathematics 14 Online
OpenStudy (abbles):

For the function defined by... Precalculus question?

OpenStudy (abbles):

For the function defined by: f(x) = \[f(x) = \left[\begin{matrix}x^2 & x \le 1 \\ 2x+1 & x<1\end{matrix}\right] \]

OpenStudy (abbles):

Pretend the brackets look like these { }

OpenStudy (abbles):

Part 1: Evaluate f(0). Part 2: Graph f(x).

Vocaloid (vocaloid):

can you check your function again and make sure the inequalities are posted correctly?

OpenStudy (sshayer):

there is some ambiguity in the question because f(0)=0 by the first equation. also f(0)=2*0+1=1 by the second eq.

OpenStudy (abbles):

Oops - the last inequality (bottom right) should be x>1

Vocaloid (vocaloid):

ok cool

OpenStudy (abbles):

Also note that the brackets on the end are actually squiggly lines { }

Vocaloid (vocaloid):

so, if x = 0, which function do we use?

OpenStudy (abbles):

Do you know how to do it?

Vocaloid (vocaloid):

yes

Vocaloid (vocaloid):

f(0) means evaluate the function when x = 0 now, this function has two rows. one row is when x >= 1 and the other row is when x < 1

OpenStudy (abbles):

f=0 would make all equations true except the bottom left one.. is that what you're asking?

Vocaloid (vocaloid):

yes, since x = 0 we only use the top row

Vocaloid (vocaloid):

so, if f(x) = x^2, when x = 0, what is f(x)?

OpenStudy (abbles):

I'm just not sure how to do it since there are four different functions... is it a matrix?

Vocaloid (vocaloid):

there are only two functions

Vocaloid (vocaloid):

good, so f(0) = 0

Vocaloid (vocaloid):

this is how the function works

Vocaloid (vocaloid):

OpenStudy (abbles):

It would equal 0

Vocaloid (vocaloid):

this means that f(x) = x^2 when x <=1

Vocaloid (vocaloid):

the second row means that f(x) = 2x + 1 when x > 1 make sense?

OpenStudy (abbles):

Hold on, let me look at this

OpenStudy (abbles):

Not quite sure what you mean

OpenStudy (abbles):

Why are we only using the top two equations?

Vocaloid (vocaloid):

there are two equations

Vocaloid (vocaloid):

the x <=1 part is not an equation, it tells us to use x^2 only when x <=1

Vocaloid (vocaloid):

since 0 is less than 1, we use x^2

Vocaloid (vocaloid):

make sense?

OpenStudy (abbles):

Oh I see

Vocaloid (vocaloid):

so, for the graphing part:

OpenStudy (abbles):

That clears things up!

Vocaloid (vocaloid):

for graphing, all you do is graph x^2 but only for x <=1

Vocaloid (vocaloid):

so your graph will look like this

OpenStudy (abbles):

So we would use the first one because x is less than or equal to 1?

Vocaloid (vocaloid):

yes

OpenStudy (abbles):

Ah okay

OpenStudy (abbles):

Thanks so much for your help! I think I got it from here

Vocaloid (vocaloid):

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