Mathematics
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OpenStudy (abbles):
For the function defined by... Precalculus question?
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OpenStudy (abbles):
For the function defined by: f(x) = \[f(x) = \left[\begin{matrix}x^2 & x \le 1 \\ 2x+1 & x<1\end{matrix}\right] \]
OpenStudy (abbles):
Pretend the brackets look like these { }
OpenStudy (abbles):
Part 1: Evaluate f(0).
Part 2: Graph f(x).
Vocaloid (vocaloid):
can you check your function again and make sure the inequalities are posted correctly?
OpenStudy (sshayer):
there is some ambiguity in the question
because f(0)=0 by the first equation.
also f(0)=2*0+1=1 by the second eq.
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OpenStudy (abbles):
Oops - the last inequality (bottom right) should be x>1
Vocaloid (vocaloid):
ok cool
OpenStudy (abbles):
Also note that the brackets on the end are actually squiggly lines { }
Vocaloid (vocaloid):
so, if x = 0, which function do we use?
OpenStudy (abbles):
Do you know how to do it?
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Vocaloid (vocaloid):
yes
Vocaloid (vocaloid):
f(0) means evaluate the function when x = 0
now, this function has two rows. one row is when x >= 1 and the other row is when x < 1
OpenStudy (abbles):
f=0 would make all equations true except the bottom left one.. is that what you're asking?
Vocaloid (vocaloid):
yes, since x = 0 we only use the top row
Vocaloid (vocaloid):
so, if f(x) = x^2, when x = 0, what is f(x)?
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OpenStudy (abbles):
I'm just not sure how to do it since there are four different functions... is it a matrix?
Vocaloid (vocaloid):
there are only two functions
Vocaloid (vocaloid):
good, so f(0) = 0
Vocaloid (vocaloid):
this is how the function works
Vocaloid (vocaloid):
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OpenStudy (abbles):
It would equal 0
Vocaloid (vocaloid):
this means that f(x) = x^2 when x <=1
Vocaloid (vocaloid):
the second row means that
f(x) = 2x + 1 when x > 1
make sense?
OpenStudy (abbles):
Hold on, let me look at this
OpenStudy (abbles):
Not quite sure what you mean
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OpenStudy (abbles):
Why are we only using the top two equations?
Vocaloid (vocaloid):
there are two equations
Vocaloid (vocaloid):
the x <=1 part is not an equation, it tells us to use x^2 only when x <=1
Vocaloid (vocaloid):
since 0 is less than 1, we use x^2
Vocaloid (vocaloid):
make sense?
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OpenStudy (abbles):
Oh I see
Vocaloid (vocaloid):
so, for the graphing part:
OpenStudy (abbles):
That clears things up!
Vocaloid (vocaloid):
for graphing, all you do is graph
x^2 but only for x <=1
Vocaloid (vocaloid):
so your graph will look like this
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OpenStudy (abbles):
So we would use the first one because x is less than or equal to 1?
Vocaloid (vocaloid):
yes
OpenStudy (abbles):
Ah okay
OpenStudy (abbles):
Thanks so much for your help! I think I got it from here
Vocaloid (vocaloid):
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