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Calculus1
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How would I maximize the function B(sqrt.x-X) if x ≥ X?
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My teacher wanted me to take the derivative and set it to zero so I could solve for x.
@satellite73
\[y = B \sqrt{x - X} \] if you derive the expression you get \[\frac{ dy }{ dx } = \frac{ b }{ 2 \sqrt{x - X} }\] You will find the derivative to be always positive and increasing (since you cannot solve it for 0). Hence there is no absolute maximum, unless you establish an upperbound for X.
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