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Find the sum of each sequence
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\[\sum_{k=1}^{40}5\] @jim_thompson5910
@ganeshie8 Which formula would you use?
that's adding forty 5's together, so it's the same as 40(5)
\[\frac{ n(n+1) }{ 2 }\] Would we use this?
Explain what you think this thing means as well as possible: \[\sum_{k=1}^{40}5\]
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Basically find the sum of the E but i tried plugging it in the formula but it didnt work
no that's for something like \[\sum_{n=1}^{40}k\] which is the sum of integers from 1 to 40
Oh yeaaa thats what i was wondering D: So we just multiply40*5
yes
Thank you 200 is the answer :D So 5 is replaced with "K" we would use the formula @peachpi
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pretty much
Oh i see so 40(40+1) cause k =1 Thanks thanks :D
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