Question

Which expression completes the equation

https://api.agilixbuzz.com/Resz/~Ey6YBAAAAAQC1bclcqhnmA.GkAha8oMT-Vdd5tD3oYWqB/19809088,B86/Assets/assessmentimages/alg%202%20pt%202%20u2l7%2010.jpg

Answer 1

woah im only in 9th grade i have yet to learn...Trigonometry? i think thats what that is lol

Answer 2

ok i did

Answer 3

I think you might just have to multiply the original by each of the options to find out

Answer 4

how would i do that?

Answer 5

could you walk me through?

Answer 6

@agent0smith

Answer 7

@AravindG

Answer 8

?

Answer 9

It's just doing algebra. Turn everything back into sine and cosine if you need to

I'll partly do the first one (i don't want to do all of them, it's tedious. I'm also skipping some steps that you should be able to figure out)
\[\Large \frac{ (\csc \theta +1) }{ \cot \theta }*\frac{ (1+\sin \theta) }{\cos \theta }=\]
\[\Large \frac{ \csc \theta +\csc \theta \sin \theta +\sin \theta +1 }{ \cot \theta \cos \theta }=\]
\[\Large \frac{ \csc \theta + 1 + \sin \theta + 1 }{ \frac{ \cos^2 \theta }{ \sin \theta } }=\]
\[\Large ( \csc \theta + \sin \theta + 2 ) *\frac{ \sin \theta }{ \cos^2 \theta }=\]
\[\Large \frac{ ( 1 + \sin^2 \theta + 2 \sin \theta ) }{ \cos^2 \theta }=\]
\[\Large \frac{ ( \sin \theta +1 )^2 }{ 1- \sin^2 \theta }= \frac{ ( \sin \theta +1 )^2 }{ (1- \sin \theta)(1+\sin \theta) }=\]
\[\Large \frac{1+ \sin \theta }{ 1 - \sin \theta }\]

Answer 10

Wait a second. What the hell are we even supposed to do with this question. I just did all this crap for nothing. The question isn't even clear.

I'm guessing we're supposed to set the thing we're given equal to one of those options? This question is dumb. We aren't given an equation.

Your question is bad and you should feel bad.

Answer 11

to make it an identity

Answer 12

http://openstudy.com/study#/updates/5760cca7e4b0a532ac10c8e3

Answer 13

\[\frac{\csc+1}{\cot}=\frac{\frac1\sin+1}{\frac\cos\sin}=\frac{1+\sin}{\cos}\]

Answer 14

Ha I'm not the only one who thinks it sucks.

I repeat

Your question is bad and you should feel bad.