Question

In the figure arc DE=118 and arc BC=48. What is m angle a?

Answer 1

http://prntscr.com/bgxbgl image<------

Answer 2

This should help :)

Answer 3

B?

Answer 4

Not Quite.

With the thereom we would substitute 118 for x and 48 for y...

\(\Huge{\angle A = \frac{1}{2} (118-48)}\)

Simplify....

\(\Huge\color{red}{\angle A=\frac{70}{2}}\)

Answer 5

35!

Answer 6

can you check another of my answers?

Answer 7

\(\Huge{\checkmark}\)

Sure!

Answer 8

http://prntscr.com/bgxi7w

Answer 9

@563blackghost

Answer 10

Im here just looking at it its kinda tricky for me..

Answer 11

Okay, can i post some others at the moment too? just for checking?

Answer 12

ok :)

Answer 13

D is your answer?

Answer 14

46. http://prntscr.com/bgxjjd
49. http://prntscr.com/bgxjpa
50. http://prntscr.com/bgxjrz

and yes D is my answer

Answer 15

You are correct :)

Answer 16

Yay! Are the others correct as well?

Answer 17

46 is correct :)

Answer 18

After 49 and 50 I have about 5 more to check :)

Answer 19

49 is incorrect use...

\(\Huge{\angle 1=\frac{1}{2}(x+y)}\)

Where x is 53 and 25 is y...

Answer 20

B 39?

Answer 21

Correct :)

Answer 22

50 is incorrect as well....

24 seems to large to be x...Now 12 and 3 would add up to make a side of 15...This triangle resembles a right triangle so we would apply Pythagorean theorem...

\(\Huge{18^{2}-15^{2}=x^{2}}\)

Answer 23

9

Answer 24

Correct ^^

Answer 25

Can I post some more?you're so helpful!

Answer 26

Sure :)

Answer 27

22. http://prntscr.com/bgxmd2
26. http://prntscr.com/bgxltf
41. http://prntscr.com/bgxkt5
45. http://prntscr.com/bgxkp8

Answer 28

22 is correct :)

Answer 29

the rest?

Answer 30

sorry i was away from the computer for a sec...

Answer 31

its ok!

Answer 32

41 is correct ^^

Answer 33

26??

Answer 34

Im not so sure about 45 i would need my math book in order to check...but its been locked out since I have already closed out my connexus :(

Answer 35

What about 26?

Answer 36

Im quite confused on that one...

You see since the triangle on the side says its a 45-45-90 triangle that would mean that both triangles are congurent so the base is a sum of 2+2+8 which would 12 in which we would add that to 8 which is the top base to get the total of 20....we would then multiply that by the height which is 4 which would make is 80 and then we would divide by 2 in which I get a sum of 40 but it doesnt seem to be an option...

Answer 37

maybe 44?

Answer 38

Wait! I found it out...

The triangle on the side says that yes it is a 45-45-90 triangle and we know of the opposite side of the angle which 4 and we want to know the adjacent side so we apply the cos ratio...

\(\Huge{\cos(45)=\frac{x}{4}}\)

What would x equal?

Answer 39

Im guessing 48

Answer 40

10

Answer 41

Not quite. Since the variable is in the numerator we would multiply 4 by cos....

\(\Huge{4 \times \cos(45) = 2\sqrt{2}}\)

Since both triangle are equal that would make the other length \(\Large{2 \sqrt{2}}\) So we would add them to 8...

\(\Huge{8+(2 \sqrt{2}+2\sqrt{2})}=13.65..\)

In which we would add that to 8...

\(\Huge{13.65+8=21.65}\)

In which we would then multiply by 4 and divide by 2 to get \(\Huge{43.31 }\) which would equal to be about 44...

Im sorry but I must get off it seems something has come up..and sorry for long explanation its for your to understand :)