Perform operations
\[\frac{ 9x }{ x-5 }+\frac{ 7x }{ 5-x }+\frac{ 9x-1 }{ x^2-25 }\]
You can do this to the 2nd denominator 5 - x = -(-5 + x) = -(x - 5) so now you have the same denominator in the first two expression and can combine \[\frac{ 9x }{ x-5 }-\frac{ 7x }{ x-5 }+\frac{ 9x-1 }{ x^2-25 }\] \[\frac{ 2x }{ x-5 }+\frac{ 9x-1 }{ x^2-25 }\]
now you need a common denominator between (x - 5) and (x² - 5). Any ideas on how to get that?
(x^2-25) = (x+5)(x-5)
First you need a COMMON denominator @savy :)
Recognizing the difference of two squares may come in handy later though.
Recall you can multiply the numerator and denominator of a fraction by any nonzero number. For example, $$\large \dfrac{2}{3} = \dfrac{2•2}{2•3} = \dfrac{4}{6}$$ Read as 2 is to 3 as 4 is to 6.
@skullpatrol i think using the difference of two squares is helpful to see how to get the common denominator. Helps to see what is "missing".
So the common denominators are x-5 and x+5, right?
Good point @agent0smith
The common denominator is (x-5)(x+5) @savy it is one number common to both fractions.
that's what i said before..
Where?
@Savy "common denominators are x-5 and x+5" that is not at all the same as saying the common denominator is (x-5)(x+5)
technically it is...
How so?
No @Savy it really is not. You have to write things in a mathematically correct way, so that others can understand them.
"Common" means ONE or more things shared between two things, right?
How are we supposed to know x-5 and x+5 doesn't mean (x-5) + (x+5)?
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