Problem: (5x^4 – 3x^3 + 6x) – (3x^3 + 11x^2 – 8x) Answer: 5x^4-6x^3 -11x^2 +14x Can you show me how to solve it? Show your work! Work it out! WILL BECOME FAN AND MEDAL AND TESTIMONIAL!! :)
Are those powers/exponents?
powers sorry
(5x^4-3x^3+6x)-(3x^3+11x^2-8x) distribute negative to the second group (5x^4-3x^3+6x)-3x^3-11x^2+8x combine like terms 5x^4-3x^3-3x^3-11x^2+6x+8x add like terms 5x^4-6x^3-11x^2+14x
find all the terms the have x to the same exponent, and "combine" those terms
the first tricky part is this – (3x^3 + 11x^2 – 8x) the "-" sign out front means -1 * (3x^3 + 11x^2 – 8x) and that means -1 times each term inside the parens
so you would multiply -1 times each term inside the parens. You should get -1 * (3x^3 + 11x^2 – 8x) becomes -1*3*x^3 + -1*11*x^2 + -1* -8 * x
people would simplify -1*3*x^3 + -1*11*x^2 + -1* -8 * x by doing -1*3 is -3 so the first term is -3*x^3 or just -3x^3 (we usually leave out the multiply sign) can you do the there two terms?
can you simplify -1*11*x^2 ?
-11x^2
@phi
yes
and this one -1* -8 * x ?
8x
yes so you should know how to change – (3x^3 + 11x^2 – 8x) into -3x^3 -11x^2 + 8x
and we use that to write (5x^4 – 3x^3 + 6x) – (3x^3 + 11x^2 – 8x) as (notice we can drop the parens): 5x^4 – 3x^3 + 6x – 3x^3 - 11x^2 + 8x
now you look for the term with the biggest exponent. It is 5x^4 there is only one term with exponent 4. we write down 5x^4 next we look for the terms with the next biggest exponent. what terms do we find ?
what terms in 5x^4 – 3x^3 + 6x – 3x^3 - 11x^2 + 8x have x with an exponent of 3 ? (and include the sign)
3x^3
-3x^3 (don't forget the minus sign) and there is another x^3 term, right ?
yep
you should find -3x^3 - 3x^3 you have -3 of x^3 plus another -3 of x^3 (it's tougher to explain with negative numbers, but we "add the coefficients" in this case -3+ -3 = -6 of x^3 in other words -3x^3 - 3x^3 = -6x^3 so far we have 5x^4 -6x^3 now look for all terms with x^2 what do you find ?
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