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Mathematics 16 Online
OpenStudy (abbles):

Shifting a parabola... horizontal reflection

OpenStudy (abbles):

Explain how the graph of the given function is a transformation of the graph y = x^2

OpenStudy (abbles):

y = (2x - 6)^2 + 5

OpenStudy (abbles):

I need someone to explain this to me, because I'm just not understanding it. The answer is: up 5, right 6, and stretched vertically by a factor of 2.

OpenStudy (mathmate):

There is no reflection, just horizontal scaling, and translation. In the general case for a parent function f(x), \(y=f(bx-h)+k\) compresses/stretches f(x) horizontally by a factor "b", and translates to the right by h, and up by k. when b>1, it's a reduction, when b<1, it's a stretch. Here b=2, h=6, k=5

OpenStudy (abbles):

According to my lesson, y = c*f(x) stretches the graph of f(x) vertically by a factor of c, whereas y = f(cx) shrinks the graph of f(x) horizontally by a factor of 1/c times as wide. Now, why would this be a vertical stretch instead of a horizontal one when the c is on the inside of the parenthesis?

OpenStudy (abbles):

Right, my bad. I meant a stretch.

OpenStudy (abbles):

So it should be a horizontal stretch then?

OpenStudy (mathmate):

Good, so the more general case is \(y=af(bx-h)+k\) where a is vertical stretching (a>1) or compression (a<1). Your parent function is f(x)=x^2.

OpenStudy (mathmate):

when b>1, it's a horizontal shrink/compression.

OpenStudy (abbles):

B is greater than 1 in the example right? B would equal 2

OpenStudy (mathmate):

exactly, a=1, b=2, h=6, k=5. It's a good formula to remember, solves the stretching/shrinking & translation cases.

OpenStudy (abbles):

My answer book says the answer to this problem is that it's stretched vertically by a factor of 2. Why would it be a vertical stretch and not a horizontal one?

OpenStudy (mathmate):

It sounds like your answer book is answer a different problem. Double check for mix-up or typos. If none, mistake in the answer book! :(

OpenStudy (abbles):

Urg. This has been perplexing me. It definitely says vertical reflection. The full answer is: The graph is shifted up 5 units and right 3 units, then stretched vertically by a factor of 2.

OpenStudy (abbles):

This is part of the lesson also, if it helps..

OpenStudy (mathmate):

If you are referring to this problem: \(y = (2x - 6)^2 + 5\) make sure it is not the following: \(y = 2(x - 5)^2 + 3\) because this seems to be what the answer seems to correspond to.

OpenStudy (mathmate):

Also, beware that horizontal shrink can be made equivalent to a vertical stretch. For example, \(f(x)=(2x-5)^2+3\) .............(1) \(=2^2(x-5/2)^2+3\) \(=4(x-5/2)^2+3\) .................(2) (1) and (2) are equivalent, but the answer for (1) is shrink horizontally by a factor of 2, translate 5 to the right, and up 3. (2) is Stretch vertically by 4, translate to the right 2.5, and up 3.

OpenStudy (mathmate):

See below for illustration. The two (red & green) lines are fused together. http://prntscr.com/bh9tfy

OpenStudy (abbles):

@mathmate The problem is in fact y = (2x - 6)^2 + 5 which is why I'm so confused.

OpenStudy (abbles):

Does anyone know the answer to this?

OpenStudy (mathmate):

The answer might have been for the twin problem: y=4(x-3)^2+5...............(2) which is mathematically equivalent to y= (2x - 6)^2 + 5 .............(1) (see my explanations earlier). For (1), it is - horizontal shrinking by a factor of 2, then translate 6 to the right, and 5 up. For (2), it is - vertical stretch of 4, translate 3 to the right, and up 5. Convince yourself, if possible, that (1) and (2) are mathematically equivalent.

OpenStudy (abbles):

The answer was "The graph is shifted up 5 units and right 3 units, then stretched vertically by a factor of 2. Neither of the examples you gave had all of those components...

OpenStudy (abbles):

Gahh. Perplexing.

OpenStudy (abbles):

I have another one that's been confusing me too (same lesson). Write a function for the graph described as a transformation of y = x^2. y=x^2 experiences a shift left by 2 units, then a horizontal shrink of factor 1/2,then a shift down of 5 units. The answer I got was y = (2x+2)^2 -5 ... it was wrong. Can you guess what the right answer was?

OpenStudy (mathmate):

"The answer was "The graph is shifted up 5 units and right 3 units, then stretched vertically by a factor of \(\color{red}{2}\). Neither of the examples you gave had all of those components..." I thought I explained the same transformations as No. (2) above? "For (2), it is - vertical stretch of 4, translate 3 to the right, and up 5. " For the vertical stretch, the book answer made a mistake. You can double check with your teacher.

OpenStudy (abbles):

Okay, I'll ask the teacher. I understand how to do all the transformations but that threw me off. If you say it's a mistake, I'll take your word for it since it doesn't really make sense.

OpenStudy (mathmate):

Yep, please do that. Bring both versions. The other is more like what the answer is expected to be, so (repeating above) The answer might have been for the twin problem: y=4(x-3)^2+5...............(2) which is mathematically equivalent to y= (2x - 6)^2 + 5 .............(1) (see my explanations earlier). For (1), it is - horizontal shrinking by a factor of 2, then translate 6 to the right, and 5 up. For (2), it is - vertical stretch of 4, translate 3 to the right, and up 5.

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