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Mathematics 15 Online
zarkam21 (zarkam21):

Help with these twooo

zarkam21 (zarkam21):

zarkam21 (zarkam21):

Would this be C=2\[\pi\] r

OpenStudy (agent0smith):

There's a shorter way. You know the whole circumference. The 70 degree arc is a 70/360 fraction of the whole circumference.

zarkam21 (zarkam21):

so divide it

OpenStudy (sshayer):

change the angle to radians then \[l=r \theta\] where l is the length of arc theta ,angle in radians r=radius

OpenStudy (sshayer):

this is general formula but you can use the method given by mr.agent0smith

zarkam21 (zarkam21):

So divide it

OpenStudy (agent0smith):

Multiply the fraction, by the circumference.

zarkam21 (zarkam21):

4.86

OpenStudy (agent0smith):

Second one you can use the formula sshayer gave. Or\[\large l = \frac{ \theta }{ 360}*2 \pi r\]

zarkam21 (zarkam21):

so its 70 over 360 right

OpenStudy (agent0smith):

This is the 2nd question now.

zarkam21 (zarkam21):

the first one is 4.86

OpenStudy (agent0smith):

Yes, we're on the 2nd now.

zarkam21 (zarkam21):

Okay lets continue

OpenStudy (agent0smith):

Plug in the angle, and the length into the formula i gave earlier. Solve for r.

zarkam21 (zarkam21):

14/360*155

OpenStudy (agent0smith):

No, the angle is the degrees. The length is in cm. r is what you need to find. \[\large l = \frac{ \theta }{ 360}*2 \pi r\]

zarkam21 (zarkam21):

Sooo 155/360?

OpenStudy (agent0smith):

Well you have to plug everything in. Write out the whole equation.

zarkam21 (zarkam21):

155/360 * 14

OpenStudy (agent0smith):

That's not an equation.

zarkam21 (zarkam21):

Umm I have no idea then

OpenStudy (agent0smith):

\[\large 14 = \frac{ 155 }{ 360}*2 \pi r\]

zarkam21 (zarkam21):

There is no radius right

zarkam21 (zarkam21):

14=2.70

OpenStudy (agent0smith):

Where is your r...?

zarkam21 (zarkam21):

Its not even provided

OpenStudy (agent0smith):

Because you're supposed to solve for r. See the equation i gave above, with r.

zarkam21 (zarkam21):

5.18

OpenStudy (agent0smith):

Looks right

zarkam21 (zarkam21):

Dang, you're the best :)

OpenStudy (agent0smith):

:)

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