An ideal gas at 65 °C occupies a volume of 2.5 L at a pressure of 3.4 atm. How many moles of gas are present in the sample? (R = 0.08206 L·atm/mol·K)
3.3 moles 0.63 moles 0.31 moles 1.6 moles
@Preetha @aaronq @sweetburger
Use the ideal gas equation \[PV=nRT\]
P: Pressure V: Volume n: no. of moles R: ideal gas constant T: Absolute temperature
Okay, would the answer be B?
@Prathamesh_M
@mathmate @Preetha @sweetburger @aaronq Can you help me?
I think u made a mistake
Be sure to enter the temperature in the Kelvin scale in the ideal gas equation.
Oh okay, i knew something was wrong. Would the answer then be D?
What about now?
Nope u would get D if u enter temperature as 65
Enter temperature as 338(Kelvin scale)
The other values are as they are given in the question
Okay I think I did it right this time. The answer would be A, right?
@Prathamesh_M
@Photon336
It's not B, it"s not D, and if it's not A, then it must be D, right? @shall29 , you're here to learn about the ideal gas law, not how to guess! @Prathamesh_M already gave you the formula PV=nRT of which you know P=3.4 atm V=2.5 L R=0.08206 L-atm/(mol- deg.K) T=65 deg.C which should be converted to 65+273.15=338.15 deg. K The only unknown that you're look for is n=number of moles. So please take out your calculator and work out n instead of guessing.
Hi @mathmate. I worked it out on my calculator and got 3.3 moles, A.
I won't confirm or deny until you show me how you did it. As @agentosmith said, the right method would give you the right answer. So the method is more important than the answer choice.
Okay sure. 3.4 x 2.5 = 8.5 0.08206 x 338.15 = 27.748589 27.748589 divided by 8.5 Then I got about 3.3
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