DESPERATE HELP!! Evaluate exactly the value of the integral. Your work must include the use of substitution and the antiderivative.
Substitute \[2x ^{4}+8x\] as t
so what do u get if u take the derivative of that?
8x3+8
Exactly!
So then what?
The latter half of the whole expression can be simply made the derivative of first half.
so what is the antiderivative in total?
did u try solving it in the above mentioned method?
I'm a little confused by substitution. Can you help me through it?
ya sure
8x^3+8 can be written as (4x^3+4)*2. So ,now can you show next step?
So does that make the entire anti derivative (4x^3+4)*2?
no u do a substitution to make ur job easier
This can be easily adjust in dt form if you keep the first half expression as t.
Adjusted*
\[\int\limits_{-1}^{0} t (8x^3+8)\]
Is that correct?
no it should be entirely in terms of t
\[2x ^{4}+8x=t\] \[(8x ^{3}+8)dx=dt\]
OK that makes sense, but how do you solve using that? Where does the interval come in?
forget about the limits of the integral for now
once u solve the integral indefinitely u can always substitute the limits later
\[(8x ^{3}+8)dx=dt\] \[(4x ^{3}+4)dx=\frac{ dt }{ 2 }\]
Or if you want to do it that way you may substitute limits like For lower limit you can go for -4 and upper is ??
Not -4 actually!
-6
The lower is -1 and the upper is 0.
No after substituition i am talking!
When you put 2x^4+8x^3 as t then your lower limit changes to -6 . Can you tell me how?
Is it because that piece is to the third power? I really don't know.
Have you studied definite integration?
Not much.
did u understand till that last part i typed?
I understand it but I dont understand how it fits in as a whole or the next step
hint: read and understand example 1(c) at the following link. http://tutorial.math.lamar.edu/Classes/CalcI/SubstitutionRuleIndefinite.aspx
Ok that makes more sense but where did the power of three go?
and is the complete thing (8x^3+8)^2 + c ??
ALong the lines of the example, u=2x^4+8x du=8x^3+8=2(4x^3+4)dx or (4x^3+4)dx=du/2 so you need to integrate \(\large \int u^3 (du)/2\)
Also, it's a definite integral, so the +C does not come in. Instead, the definite integral will be a simple number.
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