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Mathematics 8 Online
OpenStudy (erinkb99):

DESPERATE HELP!! Evaluate exactly the value of the integral. Your work must include the use of substitution and the antiderivative.

OpenStudy (erinkb99):

OpenStudy (prathamesh_m):

Substitute \[2x ^{4}+8x\] as t

OpenStudy (prathamesh_m):

so what do u get if u take the derivative of that?

OpenStudy (erinkb99):

8x3+8

OpenStudy (samigupta8):

Exactly!

OpenStudy (erinkb99):

So then what?

OpenStudy (samigupta8):

The latter half of the whole expression can be simply made the derivative of first half.

OpenStudy (erinkb99):

so what is the antiderivative in total?

OpenStudy (prathamesh_m):

did u try solving it in the above mentioned method?

OpenStudy (erinkb99):

I'm a little confused by substitution. Can you help me through it?

OpenStudy (prathamesh_m):

ya sure

OpenStudy (samigupta8):

8x^3+8 can be written as (4x^3+4)*2. So ,now can you show next step?

OpenStudy (erinkb99):

So does that make the entire anti derivative (4x^3+4)*2?

OpenStudy (prathamesh_m):

no u do a substitution to make ur job easier

OpenStudy (samigupta8):

This can be easily adjust in dt form if you keep the first half expression as t.

OpenStudy (samigupta8):

Adjusted*

OpenStudy (erinkb99):

\[\int\limits_{-1}^{0} t (8x^3+8)\]

OpenStudy (erinkb99):

Is that correct?

OpenStudy (prathamesh_m):

no it should be entirely in terms of t

OpenStudy (prathamesh_m):

\[2x ^{4}+8x=t\] \[(8x ^{3}+8)dx=dt\]

OpenStudy (erinkb99):

OK that makes sense, but how do you solve using that? Where does the interval come in?

OpenStudy (prathamesh_m):

forget about the limits of the integral for now

OpenStudy (prathamesh_m):

once u solve the integral indefinitely u can always substitute the limits later

OpenStudy (prathamesh_m):

\[(8x ^{3}+8)dx=dt\] \[(4x ^{3}+4)dx=\frac{ dt }{ 2 }\]

OpenStudy (samigupta8):

Or if you want to do it that way you may substitute limits like For lower limit you can go for -4 and upper is ??

OpenStudy (samigupta8):

Not -4 actually!

OpenStudy (samigupta8):

-6

OpenStudy (erinkb99):

The lower is -1 and the upper is 0.

OpenStudy (samigupta8):

No after substituition i am talking!

OpenStudy (samigupta8):

When you put 2x^4+8x^3 as t then your lower limit changes to -6 . Can you tell me how?

OpenStudy (erinkb99):

Is it because that piece is to the third power? I really don't know.

OpenStudy (samigupta8):

Have you studied definite integration?

OpenStudy (erinkb99):

Not much.

OpenStudy (prathamesh_m):

did u understand till that last part i typed?

OpenStudy (erinkb99):

I understand it but I dont understand how it fits in as a whole or the next step

OpenStudy (mathmate):

hint: read and understand example 1(c) at the following link. http://tutorial.math.lamar.edu/Classes/CalcI/SubstitutionRuleIndefinite.aspx

OpenStudy (erinkb99):

Ok that makes more sense but where did the power of three go?

OpenStudy (erinkb99):

and is the complete thing (8x^3+8)^2 + c ??

OpenStudy (mathmate):

ALong the lines of the example, u=2x^4+8x du=8x^3+8=2(4x^3+4)dx or (4x^3+4)dx=du/2 so you need to integrate \(\large \int u^3 (du)/2\)

OpenStudy (mathmate):

Also, it's a definite integral, so the +C does not come in. Instead, the definite integral will be a simple number.

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