Percent Question
Mary gets 1.5% raise twice per year. Which expression matches that? (Y= years, S=salary) A) s(1.5)^(2y) B) s(.015)^(2y) C) s(1.015)^(2y) D) s(1.5)^(y/2) E) s(1.015) ^ (y/2)
I know when you add (increasing by some %) it is 1+ that percent
I know it is not D or E
Or b
So is it B? I guess I just need the concept explained
okay lets say that her initial salary is "s" now it gets raised by 1.5% so then her salary becomes \(\large s \times \frac{1.5}{100}\) now again his salary will increase by 1.5% (because it increases by 1.5% twice a year) so then the salary becomes this- \(\large s \times \frac{1.5}{100} \times \frac{1.5}{100}\) try to generalize it so that you get equation for the salary she gets in the "\(y^{th}\)" year
yeah
So that means it is C.
wait you mean B or C?
Let me check the back of the book
Says C
oops i made a little mistake there wait a sec lemme correct it :p
okay lets say that her initial salary is "s" now it gets raised by 1.5% so then her salary becomes \(\large s \times \frac{101.5}{100}\) i did "101.5" because the percentage increased by 1.5% now again his salary will increase by 1.5% (because it increases by 1.5% twice a year) so then the salary becomes this- \(\large s \times \frac{101.5}{100} \times \frac{101.5}{100}\)
\(\large s \times \frac{1.5}{100}\) would mean that the salary because 1.5% of the original
but because here the salary has increased by 1.5% so we can say that the salary after increment is 101.5% of the original
Ok. I really appreciate it!!!!!
np :)
Did you get that it's s(1.015)^(2y), because it happens twice a year.
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