Question

Lets say an object X is moving in a circle. At an instant t1, (lets say when parallel to the horizontal bench) it has a velocity v. At another instant t2, after being deviated by 90 degrees the velocity remain unchanged.

My confusion arises with the components.

Horizontal Component At t1: v Horizontal Component At t2: 0
Vertical Component At t1: 0 Vertical Component At t2: v

My question is how is the horizontal component decreases to 0, even though it's not necessary that the resultant centripetal acceleration has a component opposite to the horizontal velocity?

Answer 1

@ganeshie8

Answer 2

@ParthKohli

Answer 3

yes, it is necessary that your centripetal acceleration has a component in the direction of horizontal velocity

Answer 4

In this example you can see the horizontal component has decreased even though the acceleration wasn't having any component opposite to horizontal velocity

Answer 5

are you sure?

Answer 6

There's a problem with the wording of the question.
On a circle, if the displacement has changed by 90°, then velocity must also hav turned 90°, so it cannot "remain unchanged".

Do you mean "speed" and not "velocity"?

Answer 7

It is common sense, the object's velocity will remain tangential to the circle and equal in magnitude, So as soon as it gets a vertical component the horizontal component will decrease

Answer 8

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vincent-Lyon.Fr
There's a problem with the wording of the question.
On a circle, if the displacement has changed by 90°, then velocity must also hav turned 90°, so it cannot "remain unchanged".

Do you mean "speed" and not "velocity"?
\(\color{#0cbb34}{\text{End of Quote}}\)
Apologies for that. I meant the magnitude of velocity remains unchanged

Answer 9

But the centripetal acceleration DOES have a horizontal component to the left!

Answer 10

Oh yeah got it

Answer 11

Foolish of me to ask such a simple thing