A rectangle has been drawn in such way that one vertex is on the beginning of coordinates plane, two sides are on the y and x axis, and another vertex is a point in f(x) = 4 - 2x/3. What are rectangle vertexes coordinates so that the area of the rectangle is maximum?
My attempt to solve this: The question is basically asking what is the maximum number that can be obtained when x*y (x and y represent the point in the function that would be a rectagle's vertex). Function touches y axis in point (0, 4) and x axis in point (6, 0) I think we need to find the middle point between x and y? So, it would be (3, 2) Am I right and how is it the case? (My reasoning is that the area would go lower if x or y got bigger, but I got this fact from trying different values, so it's not really solid...)
Nice to see you didn't jump to calculus the moment you saw the word "maximum"
That might be because I have very little knowledge in calculus yet ;)
But I wonder how to prove that my solution is right / wrong...
Area = x*y = x*(4-2x/3)
You must be knowing how to find the vertex point of a parabola w/o using calculus.
I am not sure what you mean, but I think that it is possible to draw a parabola g(x)=4x - 2x^2/3 and the intersection point of f(x)= 4 - 2x/3 would be the vertex point? So, basically a system of equations and then a quadratic?
No. Its very simple. You're just not looking at it correctly. Area expression is given by x(4-2x/3)
Fine with that expression ?
Yes
What geometric shape does the graph of the function A(x) = x*(4-2x/3) represent ?
parabola
What kind of parabola, facing up or facing down ?
facing down
So it will have a MAXIMUM value at the vertex. Can you find the vertex ?
Well, vertex would be x = 0, so y = 0?
No. Vertex is the turning point : |dw:1466271473534:dw|
Haven't you studied parabolas before ?
I have, but this parabola has symmetry from y axis, so the vertex would be in (0, c). So, x = 0..
Oh, yes. I got you. You're right. Find y coordinate also
If x = 0, then y = 0 as well. (0,0)
Hey no. Sorry I wasn't paying attention. You're wrong. (0,0) is not the vertex
But how comes? :D A(x)= x(4 - 2x/3) So, if x = 0, then whole RHS would be 0 and that would make y = 0
That means (0, 0) is a point on the parabola. It need not be the vertex : |dw:1466271772454:dw|
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