Can you help me with this one A ball is thrown from an initial height of 2meters with an initial upward velocity of 15m/s. The ball's height h (in meters) after t seconds is given by the following. h=2+15t-5t^2 Find all values of t for which the ball's height is 8 meters.

Question

kinged · Answer

Just substitute 8 into h and carry out the quadratic formula.

jtug6 · Answer

What kinged said but if you need further help I can guide you through the process.

noodya123 · Answer

so i got 2.5247 or 0.4753 idk if i got this correct i think its wrong

kinged · Answer

These are just the two values at which the ball is 8m high

jtug6 · Answer

Yeah those are the correct values where at that time (2.5 or 0.47) that the ball is right around 8m in height.

noodya123 · Answer

thank you both so much

noodya123 · Answer

its saying its incorrect

jtug6 · Answer

Does it want it in an approximate form, or rounded to a certain place?

jtug6 · Answer

It should specify.

noodya123 · Answer

round to the nearest hundreth it says

kinged · Answer

2.52 and 0.47

jtug6 · Answer

2.52 and 0.48

kinged · Answer

If these are wrong, then maybe you should factor in the initial hight...

jtug6 · Answer

You sure it's .47?

noodya123 · Answer

thats what i got

noodya123 · Answer

it was correct

jtug6 · Answer

Well I meant 0.4753 rounded to the hundreth's place would be 0.48 I believe ^_^

jtug6 · Answer

Because the 0.0053 is > 0.0050 so you'd round the hundreth's to the next highest value, 7 => 8 =p

mathmale · Answer

Next time, please share your actual work; that way you'll likely get better and quicker  feedback.