You invested $22,000 in two accounts paying 6% and 8% annual interest , respectively , if the total interest earned for the year is was $1700, how much was invested for each rate.
At 6%=
At 8%=

Question

You invested $22,000 in two accounts paying  6% and 8% annual interest , respectively , if the total interest earned for the year is was $1700, how much was invested for each rate.
At 6%=
At 8%=

kinged · Answer

Start with 0.06x + 0.08y = 1700
(Given that x is for first account and y is for second account.)

mathguy5 · Answer

i got 0.6+1760=0.8=1700

kinged · Answer

How does 0.8=1700?

mathguy5 · Answer

i meant minus sorry

kinged · Answer

Just discard that equation from your mind.
Think this way:
The $22,000 were separated into two accounts (with amounts x and y).
These amounts yield 6% for x and 8% for y (That's 0.06 and 0.08, respectively).

mathguy5 · Answer

0.6x0.8(22,000-x)=1700

kinged · Answer

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kinged · Answer

Discard the $22,000 from the equation for now.

mathguy5 · Answer

I got 1000 and 700 as the 2 final answers

kinged · Answer

But these numbers don't add up to $22,000 (the number you invested in both).

mathguy5 · Answer

I think its 2000 and 200 since x gives 2000 and the remaining has to be 200.

mathguy5 · Answer

i mean 20,000 and 200

kinged · Answer

20,000+200=20,200 not 22,000

mathguy5 · Answer

thanks. I mean 20,000 and 2000

mathstudent55 · Answer

Why are you guessing?
Write a system of equations, solve it, and you'll know for sure.
So far you haven't guessed the correct answer yet.

mathguy5 · Answer

after reviewing i got y=0.75x+21250

kinged · Answer

Use these two equations:
The total sum of investments in both accounts which is x+y=?
then make an equation for the yield which is 00.6x+0.08y=?

kinged · Answer

Complete these steps so that we can go on.