Find a formula for the general term an of the sequence, assuming that the pattern of the first few terms continues. {3, −1, 3, −1, 3, −1, ...}
like I know for sure, it will include (-1)^n+1 times 3 raised to something
the power of three must alternate between 0 and 1...
hmmmm
oh or (-1)^n+1 * (3+3(-1)^n+1)
noo
Maybe you can "center it" at 1, and find a way to alternate adding and subtracting 2
+2*(-1)^n+1
\[\large 1+2*(-1)^{n+1}\]starting with n=1
yay! :)
Yeah your initial attempt is what gave me the idea :)
thanks! ^_^
Since your initial attempt would alternate between 0 and 6, i just translated it
yeah it makes a lot of sense :)
You could apply that to any sequence of that form {a, -b, a, -b...} \[\frac{ a-b }{ 2 }+(a-b)*(-1)^{n+1}\]
Wait that prob isn't right. Meh, close enough
It helps though, it looks like any sequence that alternates between two numbers will include something like that
Yeah, it's the midpoint of the two numbers, plus the distance from the midpoint times the (-1)^n+1
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