How to factor 2x^2+22x+48 I am unable to find this, although I understand for the most part how to factor trinomials.
Just factor out 2
Divide the whole expression by 2 first
2x^2+22x+48 \[ 2(x^2+11x+24)\] list all ways to get 24: 1,24 2,12 3,8 4,6 we want a pair with the same sign, both +, that add to 11
You don't need to write as\[2(x ^{2}+11x+24) since the \left hand side is probably zero.\]
when you factor the expression, you do keep the 2 if you were solving an equation where the right-hand side is 0, then yes, you could simplify by dividing both sides by 2. That is not the case if you are just factoring an expression.
sometimes you factor , so that you can simplify a fraction. for example \[ \frac{2x^2+22x+48}{x+3} \]
Thank you all! I didn't understand that I had to divide by the greatest common factor first!
Which is why I wrote probably.
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