Ask your own question, for FREE!
Physics 14 Online
OpenStudy (yanasidlinskiy):

@.Sam.

OpenStudy (yanasidlinskiy):

I'm not sure how to figure this one out 27 coulombs of charge flows through a hair dryer every 3.0 seconds. What is the current flow? 9 A 0.11 A 81 A 5 A Would I divide?

OpenStudy (yanasidlinskiy):

I got 9A

OpenStudy (sachintha):

Correct!

OpenStudy (yanasidlinskiy):

A current with 12 amps flows from a hair drier for 3.0 seconds from a 120 Volt source. What is the resistance of the hair drier? 10 ohm 0.1 ohm 4 ohm<<<<<? 5 ohm

OpenStudy (sachintha):

Use Ohm's law. \(V=IR\)

OpenStudy (yanasidlinskiy):

So 10?

OpenStudy (sachintha):

You don't have to consider about time. Yes it is. :)

OpenStudy (yanasidlinskiy):

A current with 12 amps flows from a hair drier for 3.0 seconds from a 120 Volt source. What is the power of the hair drier? 1440 W 10 W 144 W 0.1 W Would I use v^2? Or something like that?

OpenStudy (sachintha):

\(Power=IV\)

OpenStudy (yanasidlinskiy):

It's A right? A 10 ohms, 22 ohms, and 100 ohms resistor are hooked in series. What is the total resistance? 6.5 ohms 132 ohms 0.16 ohms 132 volts Sorry about asking alot lol. I'm doing this right before class in college lol. I ask for forgivenesss. Not a physics geek lol. Srry

OpenStudy (sachintha):

For resistors in series, \(R_T = R_1+R_2+\ldots\) For resistors in parallel, \(\Large\frac{1}{R_T}\normalsize=\Large\frac{1}{R_1}\normalsize+\Large\frac{1}{R_2}\normalsize+\ldots\)

OpenStudy (sachintha):

Previous one is correct.

OpenStudy (yanasidlinskiy):

So how exactly would I work this one out??

OpenStudy (sachintha):

Since the resistors are in series you add them up.

OpenStudy (yanasidlinskiy):

Oh okay. A 10 ohms, 22 ohms, and 100 ohms resistor are hooked in parallel. What is the total resistance? 0.155 ohms 132 ohms 6.4 ohms 132 volts What about if they are in parallel?

OpenStudy (sachintha):

Use the other equation I gave.

OpenStudy (yanasidlinskiy):

Adding?

OpenStudy (sachintha):

\(\Large\frac{1}{R_T}\normalsize=\Large\frac{1}{R_1}\normalsize+\Large\frac{1}{R_2}\normalsize+\ldots\)

OpenStudy (yanasidlinskiy):

Would the units be volts for this one?

OpenStudy (yanasidlinskiy):

Or ohms?

OpenStudy (sachintha):

Unit of resistance is ohms.

OpenStudy (yanasidlinskiy):

2122?

OpenStudy (sachintha):

This is the correct simplified equation, \(\Large\frac{1}{R_T}\normalsize=\Large\frac{1}{R_1}\normalsize+\Large\frac{1}{R_2}\normalsize+\Large\frac{1}{R_3}\) \(R_T=\Large\frac{R_2R_3+R_1R_3+R_1R_2}{R_1+R_2+R_3}\)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!