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Mathematics 18 Online
OpenStudy (amtran_bus):

A group of 12 people exchange handshakes. How many handshakes are exchanged if each person shakes hands exactly once with each of the other people in the room?

OpenStudy (zootedyoungin):

144

OpenStudy (zootedyoungin):

24

OpenStudy (zootedyoungin):

idk

OpenStudy (amtran_bus):

U wrong

OpenStudy (amtran_bus):

Nope. Ans is 66

OpenStudy (zootedyoungin):

how is it 66

OpenStudy (amtran_bus):

I need some real help @mathstudent55 @agent0smith

OpenStudy (mathstudent55):

Here is a circle with 12 marks on it, like the hours on a clock. Connect each mark with all other marks and count them. |dw:1466526263818:dw|

OpenStudy (amtran_bus):

lol really? That would take awhile

OpenStudy (mathstudent55):

12 o'clock connected to all hours = 11 Now connect 1 o'clock to all hours. Don;t connect to 12 o'clock bec that is already done. |dw:1466526324891:dw|

OpenStudy (amtran_bus):

I just need to know why it is 66. Book says (12! 2!) / 10!

OpenStudy (mathstudent55):

That is 10 more. |dw:1466526397640:dw|

OpenStudy (amtran_bus):

ok I'm following you

OpenStudy (mathstudent55):

You see that for each following hour you connect, you have one less connection to make. You end up with 11 + 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1

OpenStudy (mathstudent55):

The sequence 1 + 2 + 3 + ... + n has a sum \(\dfrac{n (n + 1)}{2} \)

OpenStudy (amtran_bus):

Oh ok. I'm tempted to include the 12 but your illustration really helps a lot

OpenStudy (amtran_bus):

Thanks so much

OpenStudy (mathstudent55):

\(1 + 2 + 3 + ... + 10 + 11 = \dfrac{10(11)}{2} == 66\)

OpenStudy (mathstudent55):

Here are the numbers 1 through 11 displayed in a very specific way. Now we will add them vertically. |dw:1466526615917:dw|

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