Question

Derive v^2/r from Ohm's law

Answer 1

You just need

V = IR
and
P = IV

First, solve V = IR for I - just divide both sides by R\[\large I = \frac{ V }{ R }\]
Now replace the I in P = IV with that \[\large P = \frac{ V }{ R }*V\]and that's it.

Answer 2

so it would be p=v/r*v?

Answer 3

Well you simplify it... V times V = ?

Answer 4

V^2

Answer 5

so v^s/R?

Answer 6

*^2

Answer 7

Well yes, since that is what you were deriving... :P

Answer 8

So the final is... p=v/r*v

Answer 9

?

Answer 10

no lol you just wrote the final expression!

Answer 11

LOL

Answer 12

I don't get it. That's so weird. I'll never understand physics

Answer 13

It's just algebra! V*V/R is V^2/R!

Answer 14

Ik that. so for it being derived it would be v*v/R Right??

Answer 15

NO GODDAMMIT

Answer 16

The derivation is the whole thing, the first post!

Answer 17

WTF! I"M FCKN CONFUSED DUMAS

Answer 18

In my first post, the derivation is basically the whole thing, at least from the word "First,"