How to find the slope of a line
you use the slope formula
What exactly is the question here? >.<
\[m=\frac{ y _{2}-y _{1} }{ x _{2}-x _{1} }\]
That's the second time I write the same equation for you in exactly two minutes.
Noo, I understand how to get the slope @Kinged
The question I am is asking for the slope of a line
Is there any equation /co-ordinates given?
y=-5x
Since I already ask alot of questions, I wanted to do this on my own lol :) Thats why just needed guidance on finding the slop of a line
Slope
Two points make a line. So this equation makes the slope OF A LINE. Now, you can rearrange that equation into \[(y _{2} - y _{1}) = m(x _{2} - x _{1})\] And then, one of the points is unknown, it could be anywhere on the line. so instead of y-sub-2 and x-sub-2, make them variables x and y: \[(y - y _{0}) = m(x - x _{0})\] Finally, multiply: \[y - y _{0} = mx - x _{0}\] and move all the constants to one place, and call them "b"\[y = mx + (y _{0} - mx _{0})\] \[y = mx + b\]
This is the other form of a line - y = m*x + b In your case, b=0, so you should be able to look at your equation and discover m, the slope of this particular line.
So for y=-5x
I would just substitute it into the equation y=mx+b
Well, don't think of it as substituting, think of it as comparing. Compare y = (-5)*x + 0 to y = m*x + b If you write it like that, you can see what m, the slope is. Bonus: b is called the y-intercept. That means two things. When x=0, y=b, and it means y=b is the place where the line crosses the y-axis (or vertical axis)
Okay so I know that -5 is the slope definitely
Ohhh is the slope zero?
the slope is -5 and the yintercept is 0
@agent0smith
ohh its just -5 as the slope :)
Yes. For of an equation that LOOKS LIKE y = mx+b, the slope is the m, whatever number is in front of the x
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