Question

Simplifying Radicals Help

Answer 1

the attachment contains the problem

Answer 2

first reduce the exponent.
-3/6 = ?

Answer 3

-1/2

Answer 4

are you there

Answer 5

then use this rule
\[x^{-a}=\frac{1}{x^a}\]

Answer 6

so basically the exponent of -1/2 becomes positive when you move it to the numerator

Answer 7

so its \[1/\sqrt{x}\]

Answer 8

no. It's \(\sqrt{x}\)

\[\frac{ 1 }{ x^\frac{-3}{6} }=\frac{ 1 }{ x^\frac{-1}{2}}=x^\frac{1}{2}=\sqrt{x}\]

Answer 9

but wouldn't the \[\sqrt{x}\] divide 1

Answer 10

no. because the exponent is still negative

\[\frac{ 1 }{ x^\frac{-1}{2}}=\frac{ 1 }{ \frac{ 1 }{ \sqrt{x} } }=\sqrt{x}\]

Answer 11

Oh ok thanks a lot.