Can someone please check my work on this math question? please? I'll fan and give a medal!!
Solve the quadratic equation by factoring -- 3x^3 – 12x = 0
@jim_thompson5910 can you please help me?
What quantity (represented by the product of a number and a letter) represents a common factor of the given quadratic equation? If you can identify that, then please write out that common factor as the multiplier of whatever is left. correct format: wx(y - z) = 0
Be 100% certain that you know what "common factor" means in this context.
so would the common factor be x?
@agent0smith could you please try to help me?
Look at the quadratic. What common factor can you take out of both terms?
3x?
Yes.
okay then what do I do?
Take out the common factor out of both terms
what do you mean? like 3x^3 becomes 3x and 12x becomes 3x?
No. If you were factoring 5x^4 + 35x you'd write it as 5x(x^3 + 7)
I'm not sure how I would write 3x^3 – 12x = 0
@agent0smith ?
Try it.
3x(x^3 – 12) like that?
You took an x out of 3x^3 though... and a 3 out of 12. Try again
what do you mean?
3(x^3 – 9) thats what I needed?
No... taking out a factor is like dividing. You're doing it as if it's subtraction.
so 3x(x^2 – 3x)
Not that either...
okay, then idk what you mean...
You'll need to review some basics on factoring.
okay, but I was trying to write it in the format that you did this one 5x(x^3 + 7)
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