Question

Can someone help me figure out the unknown side x for the triangle below?
(in comments)

Answer 1

use pythagoras's theorem.

Answer 2

I know what that is, but I'm a bit confused on how to use it

Answer 3

\[7^2=4^2+x^2,find ~x\]

Answer 4

I was explained how to use it on a different problem a little while ago but I'm not sure how to apply it to this

Answer 5

x^2=?

Answer 6

a^2 + b^2 = c^2

Answer 7

7^2=?
4^2=?

Answer 8

then = 7^2 + 4^2 = x^2

Answer 9

That's as far as I get

Answer 10

\[7^2=7 \times7=?\]

Answer 11

i give you an example.
\[3\times3=9,6\times6=36\]

Answer 12

wait
is it the sqrt of 8?

Answer 13

\[3^2=3\times3=9\]
tell me 7*7=?

Answer 14

simple multiplication.
\[7^2=7 \times7=49\]
\[4^2=?\]

Answer 15

16

Answer 16

\[49=16+x^2\]
then \[x^2=?\]

Answer 17

x=5

Answer 18

subtract 16 from both sides

Answer 19

x=5 is not correct.

Answer 20

49 = 16 + x^2
Take the root of both sides and solve
x= sqrt 33, -sqrt33
x= 5.744,-5.744
since it cant be a negative number its 5

Answer 21

no more accurate is \[\sqrt{33}\]
it is an irrational number.
If the answer is required in decimals then only give otherwise leave under the square root.

Answer 22

So, does that mean theres no solution? or the answer is sqrt33?

Answer 23

no,
\[x=\sqrt{33}\]

Answer 24

it is a solution.

Answer 25

so the solution is sqrt33? I'm super confused

Answer 26

here i give you more examples.

Answer 27

Ok so, then x=sqrt33 is the unknown angle? @sshayer

Answer 28

oh no,it is one of the side of the right angle triangle.

Answer 29

What does that mean? How do I find the answer?

Answer 30

You literally just found the answer. Like 2 posts back.

Answer 31

find x,where it is written .
if it is written inside at the corner means you have to find the angle

Answer 32

The pythagorean theorem is \[a^2 + b^2 = c^2\]"c" is the hypotenuse (the longest side, always opposite from the right angle), and "a" and "b" are the legs of the right triangle (the other two sides)

In your problem, we can set a=4 (you can set either a=4 or b=4, but not both), and c=7.
Our equation now is \[4^2 + x^2 = 7^2\]This simplifies to \[16 + x^2=49\]and is further simplified to \[x^2=33\]We take both the positive and negative square root of 33, which is better left in radical form. This leaves us with \[x=-\sqrt{33}, \sqrt{33}\]However, you cannot have a negative side length, so the answer is \[x=\sqrt{33}\]