A train starts from rest and travels for 5.0 s with a uniform acceleration of 1.5 m/s 2. How far does the train travel in this time interval?

Question

abhisar · Answer

You can use the equation
$\sf s=0.5 \times a \times  t^2$ to find out the traveled distance.

s= distance traveled
a = acceleration
t = time

mathmale · Answer

Welcome to OpenStudy.  I encourage you to establish a dialogue with whomever else wants to help you.  Ask questions as appropriate.

Supposing that acceleration (a) is constant, then 

the formula for velocity is $$v(t)=v _{0}+at$$

mathmale · Answer

The initial velocity here is zero.  See why?

Set v_0 equal to zero.  What does your formula for v(t) look like now?

Through various methods, one can obtain a related formula for the distance traveled:$$s=s _{0}+v _{0}t+\frac{ 1 }{ 2 }t^2$$

mathmale · Answer

compare this to abhisar's suggested formula, remembering that the initial position can be assumed to be zero, as can the initial velocity.

Please show y our work if you'd like to receive feedback.

shamim · Answer

Welcome to openstudy !!!!

rvc · Answer

$\huge Welcome~ to~ OpenStudy$