A plane takes off at an angle of elevation of 15° and travels in a straight line for 3,000 meters. What is the height of the plane above the ground at this instant? 2898 m 2701 m 804 m 776 m
|dw:1467043002980:dw| Which trignometric function do we need to use? We know an angle. We're trying to find the side opposite it and we know the side adjacent to it. Remember: sin = opposite/hypotenuse cos = adjacent/hypotenuse tan = opposite/adjacent
I think perhaps the drawing needs to be edited. I think the hypotenuse is 3000m, not the bottom?
The question is not very clear. They may mean 3000 m in the direction of travel (as opposed to horizontally)
mhmm, oh yes. My bad. It should be the hypotenuse. |dw:1467043248122:dw| So which trignometric function should we use? @09h8822332e43
sin?
hello? please i need an answer
Yes, we need to use sin. sin \(\theta\) = opposite/hypotenuse can you plug in the information we were given in to it and solve for the opposite side?
sin(15) /3000 something like that?
is this plato?
yes
I would write it as sin(15) = x/3000 now "solve for x" by multiplying both sides by 3000 3000*sin(15) = x
you will need a calculator or paste into google 3000*sin(15 deg)=
thanks
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