CORRECTION
@agent0smith according to what you said, that is exactly what I did ,, but for choice A it doesn't fall into a quadrant category
So all of the above?
"lie COMPLETELY within the third quadrant"
okay okay so not that, just bcd
Thanks @agent0smith
You need to first check the radius of the given circle in choice. then look for the center of that circle. finally see if u can make a circle of that radius using the centre point without crossing into other quadrant.
Oh yeah in this one you don't JUST want the centers. I'd draw them.
try B again
So not B, C, D
No
If you plot the center, then you can use the radius to draw the circle. Remember (x-h)^2 + (y-k)^2 = r^2 Eg. (x-7)^2 + (y-5)^2 = 100 would have a radius of sqrt100 or 10.
e.g. if centre is (-3, -3), can u make a circle of radius 4 without crossing into the other quadrant.
So plot it all
Yes plot all of them.
think of it like this. -3 is telling u the minimum distance from other adjacent quadrant.
...can u draw a line of length 4 without crossing the boundary of other quadrant
the points right?
I mean the ordered pair
Draw the circle. Plot the center, then use the radius to draw the circle.
like this?
Label it better, like label the radius. You'd be better off using graph paper to do it more accurately, if you have any
No i mean label what the radius actually is. And you need to draw an x-y axes...
@agent0smith
Should be easy to choose.
Just A?
It's really easy to tell with the diagram. Which circles are inside the 3rd quadrant.
B is kind of in there at the tip
Two circles are completely inside the third quadrant, two are not.
Got it got it
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