Question

Medal!!!! if you want one

Answer 1

ill give you a medal if you can help me answer it @MathIsCancer

Answer 2

@jh99 @Kinged

Answer 3

see this to get started

http://openstudy.com/study#/updates/576c8a99e4b086f11349e3c3

Answer 4

but i do not understand any of that

Answer 5

do you agree that when you multiply two exponential expressions, such as x^2 and x^3, you add the exponents?

x^2 times x^3 = x^(2+3) = x^5

agreed? or no?

Answer 6

agreed but i don't understand where ur going with that

Answer 7

well we use that idea to figure out what goes in the blank

x^3 times _______ = x^6

just try to think in reverse of the last example

Answer 8

so the answer would be x^3

Answer 9

x^3 times x^3 = x^6, yes

Answer 10

so this means x^3 times 2x^3 = 2x^6

Answer 11

ok

Answer 12

you'll write 2x^3 over the x^3 term in the dividend

Answer 13

\[\frac{2 x^6-9 x^5+4 x^2-5}{x^3-5}=2 x^3-9 x^2+10+\frac{45-41 x^2}{x^3-5}\]

Answer 14

so its either
\[2x^3-9x^3+4x-5 \]
or
\[2x^3-9x^2+10\]
i thank its the second one but I'm not 100% sure

Answer 15

@jim_thompson5910

Answer 16

am i right

Answer 17

From Mathematica:\[\text{Together}\left[2 x^3-9 x^2+\frac{45-41 x^2}{x^3-5}+10\right] \]\[\frac{2 x^6-9 x^5+4 x^2-5}{x^3-5} \]

Answer 18

2x^3-9x^2+10 is correct

Answer 19

so is the answer \[2x^3-9x^2+10\]

Answer 20

yay thank you

Answer 21

yes